Ask question

Ask question

All categories

soldier1979 [14.2K]

4 years ago

9

Which celestial body would have the strongest gravitational pull on a satellite orbiting 100 km above its surface?

2 answers:

marshall27 [118]4 years ago

4 0

:Sample Response: Jupiter would have the strongest gravitational pull on a satellite orbiting above its surface because gravity is directly proportional to mass and Jupiter is the most massive planet.

Explanation:

8090 [49]4 years ago

3 0

According to the Law of Universal Gravitation, the gravitational force is directly proportional to the mass, and inversely proportional to the distance. In this problem, let's assume the celestial bodies to be restricted to the planets and the Sun. Since the distance is specified, the other factor would be the mass. Among all the celestial bodies, the Sun is the most massive. So, the Sun would cause the strongest gravitational pull to the satellite.

You might be interested in

Energy of a SpacecraftVery far from earth(at R=\infty), a spacecraft has run out of fuel and its kineticenergy is zero. If only

Firdavs [7]

Answer:

$s_e=\sqrt{\frac{2GM_e}{R_e^2}}$

Explanation:

In this case mechanical energy is conserved, which means that the sum of the initial kinetic energy and initial potential gravitational energy will be equal to the sum of the final kinetic energy and final potential gravitational energy:

$K_i+U_i=K_f+U_f$

Which in our case will be:

$\frac{mv_i^2}{2}+\frac{-GM_em}{r_i^2}=\frac{mv_f^2}{2}+\frac{-GM_em}{r_f^2}$

Which, since $v_i=0m/s$ , $r_i=infinity$ , $r_f=R_e$ , $v_f=s_e$ and canceling <em>m</em> means that:

$\frac{s_f^2}{2}=\frac{GM_e}{R_e^2}$

Solving for the final velocity we get:

$s_e=\sqrt{\frac{2GM_e}{R_e^2}}$

6 0

3 years ago

A 10 Ω resistor is connected to a 120-V ac power supply. What is the peak current through the resistor?

11111nata11111 [884]

Answer:

Peak current = 16.9 A

Explanation:

Given that

RMS voltage = 120 Volts

$V_{rms} = 120 V$

AC is connected across resistance

$R = 10 ohm$

now by ohm's law

$V = i R$

$120 = i (10)$

$i_{rms} = \frac{120}{10} = 12 A$

now peak value of current will be given as

$i_{peak} = \sqrt{2} i_{rms}$

$i_{peak} = \sqrt2 (12) = 16.9 A$

8 0

3 years ago

Use differentials to estimate the amount of metal in a closed cylindrical can that is 10 cm high and 10 cm in diameter if the me

lana66690 [7]

Answer:

dV = 32.98 cm³

Explanation:

We know that

V = f ( h,r)

$dV= \frac{\partial V}{\partial r}dr+ \frac{\partial V}{\partial h}dh$

We also know that

$V=\pi r^2h$

$dV= 2\pi h dr + \pi r^2 dh$

Given that

h= 10 cm

d=10 cm , r= 5 cm

Thickness = 0.05 cm so dr = 0.05 cm

The metal in the top and the bottom is 0.2 cm thick so dh = 0.2 + 0.2 cm

dh = 0.4 cm

Now by putting the values

$dV= 2\pi h dr + \pi r^2 dh$

$dV= 2\times \pi \times 5\times 0.05 + \pi \times 5^2\times 0.4\ cm^3$

dV = 32.98 cm³

8 0

3 years ago

What is plasma made of and what are its properties.<br> why do we need to study plasma in physics

Elis [28]

Plasma is made up of about 90% water. It also has salts and enzymes.

Plasma has:

no fixed shape
no fixed volume
are less dense than liquids and solids

3 0

3 years ago

Read 2 more answers

A 2000-kg truck traveling at a speed of 6.0 m/s slows down to 4.0 m/s along a straight road. What

antiseptic1488 [7]

Answer: -4000 kg • m/s

3 0

3 years ago