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soldier1979 [14.2K]
3 years ago
9

Which celestial body would have the strongest gravitational pull on a satellite orbiting 100 km above its surface?

Physics
2 answers:
marshall27 [118]3 years ago
4 0

:Sample Response: Jupiter would have the strongest gravitational pull on a satellite orbiting above its surface because gravity is directly proportional to mass and Jupiter is the most massive planet.

Explanation:

8090 [49]3 years ago
3 0
According to the Law of Universal Gravitation, the gravitational force is directly proportional to the mass, and inversely proportional to the distance. In this problem, let's assume the celestial bodies to be restricted to the planets and the Sun. Since the distance is specified, the other factor would be the mass. Among all the celestial bodies, the Sun is the most massive. So, the Sun would cause the strongest gravitational pull to the satellite.
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A train is traveling at 28 m/s. It slows to 6 m/s in 4 s. Calculate the distance the train
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The next step is -748 divide by -11 is 68 m (answer) the pic got cropped sorry

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3 years ago
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How much energy (in joules) is released when 0.06 kilograms of mercury is condensed to a liquid at the same temperature?
zvonat [6]
The answer is ....  C. 17,705.1 J
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3 years ago
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Why do we not consider the strong nuclear force when we describe the forces between atoms?
solong [7]

This is because, nuclear forces are short range forces.

The protons and neutrons are collectively called nucleons and they are found in the nucleus of an atom. These nucleons are held together by a strong attractive force called the nuclear force.

When atoms combine, they are held together by forces determined by electrons in the outermost shell. The influence of the nuclear force does not extend beyond the nucleus because they are short range forces.

Hence, we not consider the strong nuclear force when we describe the forces between atoms.

Learn more:brainly.com/question/3964366

3 0
2 years ago
Use the worked example above to help you solve this problem. An airboat with mass 4.30 102 kg, including the passenger, has an e
umka21 [38]

Answer:

a) a = 1,865 m / s²  and  b)  t = 8.1 s

Explanation:

a) Let's use Newton's second law to find acceleration, we can work the equation in scalar form because displacement and force have the same direction

         F = m .a

         a = F / m

         a = 8.02 10² /4.3 10²

         a = 1,865 m / s²

b) We use kinematic relationships in one dimension

        vf = vo + at

        vf = 0 + a t

         t = vf / a

          t = 15.1 / 1.865

          t = 8.1 s

3 0
3 years ago
I need to choose a theme for my physics assignment My experiment is finding g
Kobotan [32]
<h3>Question:</h3>

How to find g (acceleration due to gravity)

<h3>Solution:</h3>

We know,

Acceleration due to gravity (g)

=  \frac{GM}{ {R}^{2} }

where, G = Gravitational constant

= 6.67 \times  {10}^{11} N {m}^{2}/k {g}^{2}  \\

M = Mass of the earth

= 6 \times  {10}^{24} \:  kg

R = Radius of the earth

= 6.4 \times  {10}^{6} m

Putting these values of G, M and R in the above formula, we get

g \:  =  \:  \frac{6.67 \times  {10}^{11} N {m}^{2}/k {g}^{2}   \times \: 6 \times  {10}^{24} \:  kg }{(6.4 \times  {10}^{6}m {)}^{2}  }  \\  = 9.8m/ {s}^{2}

So, the value of acceleration due to gravity is

9.8m/s ^{2}

Hope it helps.

Do comment if you have any query.

5 0
2 years ago
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