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soldier1979 [14.2K]
4 years ago
9

Which celestial body would have the strongest gravitational pull on a satellite orbiting 100 km above its surface?

Physics
2 answers:
marshall27 [118]4 years ago
4 0

:Sample Response: Jupiter would have the strongest gravitational pull on a satellite orbiting above its surface because gravity is directly proportional to mass and Jupiter is the most massive planet.

Explanation:

8090 [49]4 years ago
3 0
According to the Law of Universal Gravitation, the gravitational force is directly proportional to the mass, and inversely proportional to the distance. In this problem, let's assume the celestial bodies to be restricted to the planets and the Sun. Since the distance is specified, the other factor would be the mass. Among all the celestial bodies, the Sun is the most massive. So, the Sun would cause the strongest gravitational pull to the satellite.
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Energy of a SpacecraftVery far from earth(at R=\infty), a spacecraft has run out of fuel and its kineticenergy is zero. If only
Firdavs [7]

Answer:

s_e=\sqrt{\frac{2GM_e}{R_e^2}}

Explanation:

In this case mechanical energy is conserved, which means that the sum of the initial kinetic energy and initial potential gravitational energy will be equal to the sum of the final kinetic energy and final potential gravitational energy:

K_i+U_i=K_f+U_f

Which in our case will be:

\frac{mv_i^2}{2}+\frac{-GM_em}{r_i^2}=\frac{mv_f^2}{2}+\frac{-GM_em}{r_f^2}

Which, since v_i=0m/s, r_i=infinity, r_f=R_e, v_f=s_e and canceling <em>m</em> means that:

\frac{s_f^2}{2}=\frac{GM_e}{R_e^2}

Solving for the final velocity we get:

s_e=\sqrt{\frac{2GM_e}{R_e^2}}

6 0
3 years ago
A 10 Ω resistor is connected to a 120-V ac power supply. What is the peak current through the resistor?
11111nata11111 [884]

Answer:

Peak current = 16.9 A

Explanation:

Given that

RMS voltage = 120 Volts

V_{rms} = 120 V

AC is connected across resistance

R = 10 ohm

now by ohm's law

V = i R

120 = i (10)

i_{rms} = \frac{120}{10} = 12 A

now peak value of current will be given as

i_{peak} = \sqrt{2} i_{rms}

i_{peak} = \sqrt2 (12) = 16.9 A

8 0
3 years ago
Use differentials to estimate the amount of metal in a closed cylindrical can that is 10 cm high and 10 cm in diameter if the me
lana66690 [7]

Answer:

dV = 32.98 cm³

Explanation:

We know that

V = f ( h,r)

dV= \frac{\partial V}{\partial r}dr+ \frac{\partial V}{\partial h}dh

We also know that

V=\pi r^2h

dV= 2\pi h dr + \pi r^2 dh

Given that

h= 10 cm

d=10 cm ,  r= 5 cm

Thickness = 0.05 cm so  dr = 0.05 cm

The metal in the top and the bottom is 0.2 cm thick  so dh = 0.2 + 0.2 cm

dh = 0.4 cm

Now by putting the values

dV= 2\pi h dr + \pi r^2 dh

dV= 2\times \pi \times 5\times 0.05 + \pi \times 5^2\times 0.4\ cm^3

dV = 32.98 cm³

8 0
3 years ago
What is plasma made of and what are its properties.<br> why do we need to study plasma in physics
Elis [28]

Plasma is made up of about 90% water. It also has salts and enzymes.

Plasma has:

  • no fixed shape
  • no fixed volume
  • are less dense than liquids and solids

3 0
3 years ago
Read 2 more answers
A 2000-kg truck traveling at a speed of 6.0 m/s slows down to 4.0 m/s along a straight road. What
antiseptic1488 [7]
Answer: -4000 kg • m/s

3 0
3 years ago
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