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2 years ago

11

what would happen to the temperature on mercury during the day if a sunspot was directly in line with it's surface?

1 answer:

QveST [7]2 years ago

3 0

Answer:

mind-bogglingly hot

Explanation:

If a sunspot were pointed right at Mercury in this way, the planet would become even more mind-bogglingly hot. Sunspots look dark in our visual spectrum, so we might suspect that they are colder (or at least less hot) than the rest of the Sun; but in fact, they are hotter.

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The property of matter that describes what it is made of

const2013 [10]

Answer:

Miixture

Explanation:

The answer is mixture

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3 years ago

Out of aluminum,copper,steel,and glass.Which material do you think will be the best thermal conductor?

Nastasia [14]

I believe it is copper

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3 years ago

Driving your Ferrari through the Italian countryside at a speedy 88 m/s, you approach an opera diva singing a high C (1,046 Hz).

MrRissso [65]

Answer:

You will hear the note E₆

Explanation:

We know that:

Your speed = 88m/s

Original frequency = 1,046 Hz

Sound speed = 340 m/s

The Doppler effect says that:

$f' = \frac{v \pm v0 }{v \mp vs}*f$

Where:

f = original frequency

f' = new frequency

v = velocity of the sound wave

v0 = your velocity

vs = velocity of the source, in this case, the source is the diva, we assume that she does not move, so vs = 0.

Replacing the values that we know in the equation we have:

$f' = \frac{340 m/s + 88m/s}{340 m/s} *1,046 Hz = 1,316.73 Hz$

This frequency is close to the note E₆ (1,318.5 Hz)

7 0

3 years ago

When is there the least amount of heat transfer within a liquid

Annette [7]

In the beginning, the melting stage they call it.

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3 years ago

Read 2 more answers

As part of your daily workout, you lie on your back and push with your feet against a platform attached to two stiff springs arr

zmey [24]

Answer:

F =1490.9 N

Explanation:

given,

work done = 82 J

compression length = 0.220 m

for parallel combination

$k_{eq}= k_1+k_2$

= 2 k

work done

$w = \dfrac{1}{2}k_{eq}x^2$

$k_{eq} = \dfrac{2W}{x^2}$

$k_{eq} = \dfrac{2\times 82}{0.22^2}$

$k_{eq} =3388.43 N/m$

force =

F = kx

F = 3388.43 ×0.22

F =745.45 N

the additional work done

final potential energy = $\dfrac{1}{2}k_{eq}(2x)^2$

= 4 W = 328 J

the additional work = 328 - 82 = 255 J

maximum force

F = k × 2x

F = 2×745.45

F =1490.9 N

6 0

3 years ago