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3 years ago

15

Whats 3/4 as a decimal

2 answers:

pentagon [3]3 years ago

8 0

Since this is out of 4, you can think of 4 as being 1. Now each part of 4 needs to have an equal value so you need to split 1 into 4 equal values. So half of 1 is 0.5 and half of 0.5 is 0.25. So, each part of 4 has a value of 0.25.

1/4 = 0.25
2/4 = 0.50
3/4 = 0.75

siniylev [52]3 years ago

3 0

.75 is it because it is like quarters. MONEY

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HELP<br> Factor<br> 6x^2+10x-4

Nimfa-mama [501]

Answer:

46x-4 i think

6x^2= 36x

36x + 10x = 46x

so 46x-4 is the answer

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3 years ago

Trudy bought a $20 prepaid long distance phone card. for every minute that she talks, $0.25 is deducted from her card. The funct

Aleksandr-060686 [28]

Answer:

Step-by-step explanation:

Given the function f(m)=20-0.25m to represent the amount of money f(m) she has left after talking m minutes, the zero of the equation can be gotten by setting f(m) to 0

f(m)=20-0.25m

0 =20-0.25m

-20 = -0.25m

m = -20/-0.25

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Hence Trudy will have talked for 80minutes if she has no money left

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3 years ago

Which equation is represented by the graph?

Scorpion4ik [409]

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7 0

3 years ago

Brady made a scale drawing of a rectangular swimming pool on a coordinate grid. The points (-20, 25), (30, 25), (30, -10) and (-

djverab [1.8K]

Answer:

Length = 50 units

width = 35 units

Step-by-step explanation:

Let A, B, C and D be the corner of the pools.

Given:

The points of the corners are.

$A(x_{1}, y_{1}})=(-20, 25)$

$B(x_{2}, y_{2}})=(30, 25)$

$C(x_{3}, y_{3}})=(30, -10)$

$D(x_{4}, y_{4}})=(-20, -10)$

We need to find the dimension of the pools.

Solution:

Using distance formula of the two points.

$d(A,B)=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ ----------(1)

For point AB

Substitute points A(30, 25) and B(30, 25) in above equation.

$AB=\sqrt{(30-(-20))^{2}+(25-25)^{2}}$

$AB=\sqrt{(30+20)^{2}}$

$AB=\sqrt{(50)^{2}$

AB = 50 units

Similarly for point BC

Substitute points B(-20, 25) and C(30, -10) in equation 1.

$d(B,C)=\sqrt{(x_{3}-x_{2})^{2}+(y_{3}-y_{2})^{2}}$

$BC=\sqrt{(30-30)^{2}+((-10)-25)^{2}}$

$BC=\sqrt{(-35)^{2}}$

BC = 35 units

Similarly for point DC

Substitute points D(-20, -10) and C(30, -10) in equation 1.

$d(D,C)=\sqrt{(x_{3}-x_{4})^{2}+(y_{3}-y_{4})^{2}}$

$DC=\sqrt{(30-(-20))^{2}+(-10-(-10))^{2}}$

$DC=\sqrt{(30+20)^{2}}$

$DC=\sqrt{(50)^{2}}$

DC = 50 units

Similarly for segment AD

Substitute points A(-20, 25) and D(-20, -10) in equation 1.

$d(A,D)=\sqrt{(x_{4}-x_{1})^{2}+(y_{4}-y_{1})^{2}}$

$AD=\sqrt{(-20-(-20))^{2}+(-10-25)^{2}}$

$AD=\sqrt{(-20+20)^{2}+(-35)^{2}}$

$AD=\sqrt{(-35)^{2}}$

AD = 35 units

Therefore, the dimension of the rectangular swimming pool are.

Length = 50 units

width = 35 units

7 0

3 years ago

What is 27.773 to its nearest tenth

Olenka [21]

Check the hundredth position after the decimal point.

This = 7 so we add 1 to the tenth position so 7 becomes 7+1 = 8

Answer is 27.8 to nearest tenth

7 0

3 years ago