A stone is thrown straight up. While the stone is rising: Group of answer choices its acceleration is upward and decreasing its
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The definition of gravitational potential energy would gravitate allows to find the answers for the energy of each object on the highest rung of the ladder are:
a) expression for gravitational potential energy is
b) Energy value
* Body 1 U_p = 82 J
* Body 2 U_p = 38.6 J
* Body 3 18.5 J
The gravitational potential energy is a configuration energy that represents the amount of work that the system can do for a given configuration, its expression is
Where is the gravitational potential energy, m the mass of the body and Δy the difference in height.
In this case it indicates that the minimum height is at the bottom and is equal to zero, the steps of a ladder have a height of approximately y = 15 cm = 0.15 m
They indicate the mass of the bodies are m₁ = 3.10 kg, the mass of the body 2 m₂ = 1.46 kg , the mass of the third object is not observed, suppose it is m₃ = 0.7 kg.
They indicate that the body is placed on the last step, suppose it is a standard 18-step ladder, therefore the total height is
y = # _ steps y_each step
y = 18 0.15
y = 2.70 m
the gravitational potential energy to the capacity of the body is
body 1
= m₁ g Δy₁
U_p = 3.10 9.8 (2.70 -0)
U_p = 82 J
body 2
U_p = 1.46 9.8 ( 2.7-0)
U_p = 38.6 J
body 3
U_pUp = 0.70 9.8 (2.7-0)
U_p = 18.5 J
In conclusion, using the definition of gravitational potential energy, we can find the answers for the energy of each object on the highest rung of the ladder are;
a) expression for gravitational potential energy is
b) Energy value
* Body 1 U_p = 82.0 J
* Body 2 U_p = 38.6 J
* Body 3 U_p = 18.5 J
Learn more here: brainly.com/question/3884855
The final magnification will be 400-fold or 400 times the original size of the object.
For magnifying smaller objects, a compound microscope is used.
A compound microscope consists of an objective and an eyepiece, whose diagram is shown in the adjoining image.
The lens near the object is called an objective and the other one is the eyepiece.
Let the magnification of the objective be m1
Let the magnification of the eyepiece be m2
The final magnification by the microscope, M, will be
M = m1 x m2
Putting the values in the above equation
M = 40 x 10
M= 400
Thus, the final magnification will be 400-fold or 400 times the original size of the object.
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Answer:
A. 216.36
B. 96.56
Explanation:
Let be the distance in first part.
= velocity × time
= 85 ×
= 49.58 km
Let be the distance in first part.
= 130 km
Average velocity =
When second leg of the trip is
A. Toward north
Average velocity = }{Total time} [/tex]
Average velocity =
Average velocity =216.36
B. Toward south
Average velocity = }{Total time} [/tex]
Average velocity =
Average velocity =96.56