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natima [27]
3 years ago
9

If a point has 40 J of energy and the electric potential is 8 V, what must be the charge?

Physics
2 answers:
Alekssandra [29.7K]3 years ago
8 0

If a point has 40 J of energy and the electric potential is 8 V, the charge must be: A. 5 C

<u>Given the following the details;</u>

  • Energy = 40 Joules
  • Electric potential = 8 Volts

To find the quantity of charge;

Mathematically, the quantity of charge with respect to electric potential is given by the formula;

Quantity \; of \; charge = \frac{Energy}{Electric \; potential}

Substituting the values into the formula, we have;

Quantity \; of \; charge = \frac{40}{8}

<em>Quantity of charge = 5 Coulombs</em>

Therefore, the quantity of charge must be <em>5 Coulombs.</em>

Find more information: brainly.com/question/21808222

s344n2d4d5 [400]3 years ago
8 0
  • Energy=E=40J
  • Potential difference=V=8V
  • Charge=Q

\boxed{\sf E=QV}

\\ \rm\longmapsto Q=\dfrac{E}{V}

\\ \rm\longmapsto Q=\dfrac{40}{8}

\\ \rm\longmapsto Q=5C

Hence total charge must be 5C.

Note:-

SI unit of charge is Coulomb (C)

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1)

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2)

When the rocket reaches an altitude of 5000 m, its acceleration has increased to

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\Delta m = m-m'=1.9\cdot 10^4 - 1.80\cdot 10^4 = 0.10\cdot 10^4 kg

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