Question

If a point has 40 J of energy and the electric potential is 8 V, what must be the charge?

Answer 1

If a point has 40 J of energy and the electric potential is 8 V, the charge must be: A. 5 C

Given the following the details;

• Energy = 40 Joules

• Electric potential = 8 Volts

To find the quantity of charge;

Mathematically, the quantity of charge with respect to electric potential is given by the formula;

$Quantity \; of \; charge = \frac{Energy}{Electric \; potential}$

Substituting the values into the formula, we have;

$Quantity \; of \; charge = \frac{40}{8}$

Quantity of charge = 5 Coulombs

Therefore, the quantity of charge must be 5 Coulombs.

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Answer 2

• Energy=E=40J
• Potential difference=V=8V
• Charge=Q

$\boxed{\sf E=QV}$

$\\ \rm\longmapsto Q=\dfrac{E}{V}$

$\\ \rm\longmapsto Q=\dfrac{40}{8}$

$\\ \rm\longmapsto Q=5C$

Hence total charge must be 5C.

Note:-

SI unit of charge is Coulomb (C)