Question

Block 1 is attached to a spring and oscillates on a horizontal frictionless surface. When block 1 is at a point of maximum displacement, block 2 is placed on top of it from directly above without interrupting the oscillation, and the two blocks stick together. How do the maximum kinetic energy

Answer 1

Answer:

Explanation:

Suppose mass of block 1 is $m_1$ and $m_2$ of block 2

For original system

natural frequency of oscillation is given by

$\omega _1=\sqrt{\frac{k}{m_1}}$

Maximum kinetic Energy is equal to total Energy of the system

$K=\frac{1}{2}kA^2$

where k=spring constant

A=maximum amplitude

Now Block B is Placed at block 1 at maximum amplitude such that A=A'

i.e. new amplitude=old amplitude

Maximum kinetic energy of combined system is

$K=\frac{1}{2}kA'^2$

as  the total energy is independent of mass therefore maximum kinetic energy  will remain same