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3 years ago

A soccer has been kicked as far as it can get with an initial momentum of 153 kg*m/s and the

Physics

1 answer:

Georgia [21]3 years ago

4 0

Answer:

85 m/s

Explanation:

The formula for momentum is product of weight and velocity

p=mv where m is mass and v is velocity

Given that;

Momentum = 153 kg*m/s

Weight = 1.8 kg

Velocity = ?

p=mv

153 = 1.8 * v

153/1.8 = v

85 m/s

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A torque acts on a wheel rotating at 19.8 rad/s and increases its angular speed to 23.5 rad/s in 11.2 s. Find the angle through

faltersainse [42]

243 rad is the angle through which the wheel turns during this time.

<h3>What is torque and angular speed?</h3>

Torque is a measure of the force that can cause an object to rotate about an axis.

Angular speed is define as the measuring angle of rotation over a given amount of time.

Mathematically , ω = θ t

From the given question ,

Torque = 19.8 rad/s

ω = 23.5 rad/s

t = 11.2 s

We get the equation,

$\frac{ 19.8 +23.5}{2} * 11.2$

= 243 rad

Learn more about Angular momentum here:

brainly.com/question/15104254

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7 0

3 years ago

The small piston of a hydraulic lift has a diameter of 8.0 cm, and its large piston has a diameter of 40cm. the lift raises a lo

Elena L [17]

Sm = small piston
la = large piston

P=F/A
P=15000/(20^2)π

F of sm = PA
= (75/2π)•((8^2)π)
= (75•64)/2
= 4800/2
= 2400N
We already know the pressure but giving it in an approximate decimal form, to two significant figures (since that's what your supplied precision is at):

a) 12 Pa
b) 2400 N

7 0

3 years ago

Read 2 more answers

A small but measurable current of 1.2 10-10A exists in a copper wire whose diameter is 2.0 mm. Assume the current is uniform. (a

Rom4ik [11]

Q: A small but measurable current of 1.2×10⁻¹⁰A exists in a copper wire whose diameter is 2.0 mm. Assume the current is uniform. (a) Calculate the current density.

Answer:

3.82×10⁻⁵ A/m

Explanation:

Current density: This can be defined as the amount of charge passing through a conductor, per unit area, per unit time. The S.I unit of current density is A/m²

From the question above, the expression for current density is given as,

τ = I/A............... Equation 1

Where τ = current density of the copper wire, I = current flowing through the copper wire, A = cross sectional area of the copper wire

But,

A = πd²/4................. Equation 2

Substitute equation 2 into equation 1

τ = 4I/(πd²)............ Equation 3

Given: I = 1.2×10⁻¹⁰ A, d = 2 mm = 2×10⁻³ m, π = 3.14

Substitute into equation 3

τ = 4(1.2×10⁻¹⁰)/[3.14×(2×10⁻³)²]

τ = (4.8×10⁻¹⁰)/(1.256×10⁻⁵)

τ = 3.82×10⁻⁵ A/m

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3 years ago

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The point is at the edge of the disk and the component bodies are:

Murrr4er [49]

Answer:

a. A uniform disk of radius and mass .

Explanation:

The moment of inertia I of an object depends on a chosen axis and the mass of the object. Given the axis through the point, the inertia will be drawn from the uniform disc having a radius and the mass.

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3 years ago

Are the two bulbs acting as current dividers or potential dividers? Explain your answer

erastova [34]

Circuits are also known as current divider circuits because, in these circuits, the current is divided through each resistor. Whereas, series circuits are known as voltage divider circuits because here voltage is divided across all the resistors.

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2 years ago