Answer:
Kc = 2.34 mol*L
Explanation:
The calculation of the Kc of a reaction is performed using the values of the concentrations of the participants in the equilibrium.
A + B ⇄ C + D
Kc = [C] * [D] / [A] * [B]
According to the reaction
Kc = [SO2]^2 * [O2]^2 / [SO3]^2
Knowing the 0.900 mol of SO3 is placed in a 2.00-L it means we have a 0.450 mol/L of SO3
0.450 --> 0 + 0 (Beginning of the reaction)
0.260 --> 0.260 + 0.130 (During the reaction)
0.190 --> 0.260 + 0.130 (Equilibrium of the reaction)
Kc = [0.260]^2 + [0.130]^2 / [0.190]^2
Kc = 2.34 mol*L
Answer:
The answer is: phospholipid molecules
Explanation:
The plasma membrane of a cell is consists of a lipid bilayer. This lipid bilayer, also known as the phospholipid bilayer, is a polar membrane composed of two layers of lipid molecules, usually amphipathic phospholipid molecules.
The amphipathic phospholipid molecules have a hydrophilic phosphate head on the exterior and a hydrophobic tail consisting of fatty acid chain on the interior of the membrane.
The location of the negative charges is evenly distributed throughout the entire atom.
J. J. Tomson concluded that atoms are divisible and that the corpuscles are their building blocks.
Atoms are made up of smaller particles.
J. J. Thomson discovered the electron ( the negative charges of the atom) in 1897.
His "plum pudding" model (1904) suggested: the electrons are embedded in the positive charge and evenly distributed throughout the entire atom.
With this model, he abandoned his earlier hypothesis that the atom was composed of immaterial vortices.
Later, Rutherford demonstrate that J.J Thompson's Plum Pudding model was not accurate.
More info about Thomson’s plum pudding model: brainly.com/question/6319700
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The dissociation of calcium carbonate, CaCO3, to simpler compounds can be expressed as,
CaCO3 --> CaO + CO2
The precipitate is CaO and its amount is calculated through the difference which will give us the answer of 5.6 g.
There are 1,000 milligrams (mg) in one gram:
In 10 grams, there are 10 x 1,000 = 10,000 milligrams. This is a lethal dose of caffeine.
There are 4.05 mg/oz (milligrams/ounce) of caffeine in the soda.
In a 12 ounce can, there are 4.05 x 12 = 48.6 milligrams.
How many sodas would it take to kill you?
To find this, we divide the lethal dose amount (10,000 mg) by the amount of caffeine per can (48.6 mg).
10,000 ÷ 48.6 = 205.76.
Since 205 cans is not quite 10,000 mg, technically it would take 206 cans of soda to consume a lethal dose of caffeine.
