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3 years ago

What is the process of intentionally interfering with the breeding process to encourage certain traits over others.

Chemistry

2 answers:

insens350 [35]3 years ago

7 0

Answer:

I thin the artificial selection is the answer it also fits the spaces

Explanation:

ok so I went in did the crossword answers are

1. biotechnology

2. DNA

3. transgenic animals

4. Genetic Engineering

5. plant

6. transgenic crop

7. Artificial Selection

8. food

9. clones

10. reproduction

skelet666 [1.2K]3 years ago

6 0

<h2>Answer:</h2>

The process of intentionally interfering with the breeding process to encourage certain traits over others is called artificial selection or selective breeding.

<h3>Explanation:</h3>

In selective breeding, the breeding of plants and animals are done intentionally to produce desirable traits. Organisms with the desired traits, such as size or taste, are artificially mated or cross-pollinated with organisms with similar desired traits. The deliberate exploitation of selective breeding to produce desired results has become very common in agriculture and experimental biology. In this way, the scientists control and introduce the desirable traits in plants and animals.

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A sample of gas in a 14.6 L flexible container is at 25.0oC and 1.00atm. What is the volume of the sample when heated to 220.0oC

inn [45]

Answer: 24.1 L

Explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=14.6L\\T_1=25.0^oC=(25+273)K=298K\\V_2=?\\T_2=220.0^0C=(220+273)K=493K$

Putting values in above equation, we get:

$\frac{14.6}{298K}=\frac{V_2}{493}\\\\V_2=24.1L$

Thus the volume of the sample when heated to 220.0oC and the pressure is constant is 24.1 L

7 0

3 years ago

Calculate the pH of a solution created by placing 2.0 grams of yttrium hydroxide, Y(OH)3, in 2.0 L of H2O. Ksp for Y(OH)3 is 6.0

oee [108]

Answer:

pH = 8.314

Explanation:

Y(OH)3(s) ↔ Y+ + 3OH-

equil: S S 3S

∴ Ksp = [ Y+ ] * [ OH- ]³ = 6.0 E-24

⇒ 6.0 E-24 = ( S )*( 3S )³

⇒ 6.0 E-24 = 27S∧4

⇒ 2.22 E-25 = S∧4

⇒ ( 2.22 E-25 )∧(1/4) = S

⇒ S = 6.866 E-7 M

⇒ [ OH- ] = 3*S =2.06 E-6 M

⇒ pOH = - Log [ OH- ]

⇒ pOH = - Log ( 2.06 E-6 )

⇒ pOH = 5.686

∴ pH = 14 - pOH

⇒ pH = 8.314

8 0

3 years ago

Minor partial melting in the asthenosphere causes liquid magma to form. If the molten rock is able to move at all, it will leave

Bad White [126]

I don’t understand the question be more specific or take a picture

6 0

3 years ago

In a reaction, 25 grams of reactant

Vsevolod [243]

Answer:

D. 15g

Explanation:

The law of conservation of mass states that, in a chemical reaction, mass can neither be created nor destroyed. This means that the amount of matter in the elements of the reactants must be equal to the amount in the resulting products.

In this question, 25 grams of a reactant AB, was broken down in a reaction to produce 10 grams of products A and X grams of product B. According to the law of conservation of mass, the mass of the reactant must be equal to the total mass of the products. This means that 25 grams must also be the total mass of both products in this reaction. Hence, if product A is 10 grams, product B will be 25 grams - 10 grams = 15 grams.

Therefore, product B must be 15 grams in order to form a total of 25 grams when added to the mass of product A. This will equate the mass of the reactant AB and fulfill the law of conservation of mass.

8 0

3 years ago

explain why some metal occur as free element in nature, why other occur in combined states. give two examples of each type

MaRussiya [10]

Explanation:

Thus, those metals which remain unaffected by moisture, oxygen and carbon dioxide of the air can occur native or free. In other words, the unreactive metals occur in nature in free state because of their low reactivity towards chemical reagents. ... Metals usually occur in combination with nonmetallic elements.

3 0

2 years ago