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Shtirlitz [24]
3 years ago
11

What is the process of intentionally interfering with the breeding process to encourage certain traits over others.

Chemistry
2 answers:
insens350 [35]3 years ago
7 0

Answer:

I thin the artificial selection is the answer it also fits the spaces

Explanation:

ok so I went in did the crossword answers are

1. biotechnology

2. DNA

3. transgenic animals

4. Genetic Engineering

5. plant

6.  transgenic crop

7. Artificial Selection

8. food

9. clones

10. reproduction

skelet666 [1.2K]3 years ago
6 0
<h2>Answer:</h2>

The process of intentionally interfering with the breeding process to encourage certain traits over others is called artificial selection or selective breeding.

<h3>Explanation:</h3>

In selective breeding, the breeding of plants and animals are done intentionally to produce desirable traits. Organisms with the desired traits, such as size or taste, are artificially mated or cross-pollinated with organisms with similar desired traits. The deliberate exploitation of selective breeding to produce desired results has become very common in agriculture and experimental biology. In this way, the scientists control and introduce the desirable traits in plants and animals.

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Explanation:

Given -

  • An organic compound gives H₂ gas with Na
  • On treatment with alkaline iodine it gives yellow ppt.
  • On oxidation with CrO₃/H⁺ forms an aldehyde (C₂H₄O)

To Find -

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Now,

Let A be the organic compound.

Then,

  1. A + Na → + H₂↑
  2. A + I₂ → CHI₃ (yellow ppt.)
  3. A + CrO₃ + H⁺ → C₂H₄O

Now,

Here we see that compound A reacts with chromic oxide (CrO₃) in the presence of acidic medium gives aldehyde.

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And It forms only 2 Carbon aldehyde it means, It is Ethanal (CH₃CHO).

Compound A reacts with chromic oxide (CrO₃) in the presence of acidic medium gives ethanal.

It means,

We know that 1° alcohol on oxidation gives aldehyde.

Here it gives 2 Carbon aldehyde.

It means,

Here 2 Carbon and 1° alcohol is used.

Now,

Its cleared that Compound A is Ethanol.

Reaction Involved -

  1. CH₃CH₂OH + Na → CH₃CH₂O⁻Na⁺ + H₂↑
  2. CH₃CH₂OH + I₂ + OH⁻ → CHI₃↓ + HCOO⁻ + HI + H₂O
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