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1 year ago

Help will name brainliest

Mathematics

1 answer:

raketka [301]1 year ago

7 0

Answer:

14y-13y² is the answer. sorry for dirty handwriting

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Find the value of x <br>

den301095 [7]

x = 20 is the answer.

<u>Step-by-step explanation:</u>

When a parallel lines cut by a transversal, then the alternate exterior angles are congruent.

So the given 2 angles add up to 180 degrees.

5x+ 9 + 3x+ 11 = 180

8x + 20 = 180

8x = 180 - 20 = 160

x = 160/8 = 20

5 0

3 years ago

What is the probability of rolling a sum of 11 on a standard pair of six-sided dice? express your answer as a fraction or a deci

FromTheMoon [43]

I think it would have to be 5 and 6 because those two make up 11 when you add them. hope this helps

8 0

3 years ago

X^2 + 8x + c<br> What is c ?

katrin [286]

Answer:

C is a constant ( a value that doesn't change)

Step-by-step explanation:

for example (X^2), here x is a variable with an exponent. (8x), here 8 is a coefficient. making c a constant.

8 0

3 years ago

If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by

Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by $y = 70t-16t^2$ .

To find : The average velocity for the time period beginning when t = 2 and lasting. a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

$(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}$

$(\text{Average velocity})_{0.1\ s}=696\ ft/s$

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

$(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}$

$(\text{Average velocity})_{0.01\ s}=7536\ ft/s$

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

$(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}$

$(\text{Average velocity})_{0.001\ s}=75936\ ft/s$

5 0

3 years ago

Harper has $15.00 to spend at her grocery store. She is going to buy bags of fruit that cost $4.75 each and one box of crackers

Andrej [43]

First write the inequality: 15 $\leq$ 4.75x +3.50

Then to solve, first subtract 3.50 from both sides to get:

11.50 $\leq$ 4.75x

Then divide by 4.75 to get 2.42, and since you can't buy .42 of a bag of fruit, you round down. So your final answer would be 2 bags of fruit.

7 0

2 years ago

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