Question

A pool is 31.4 m long and 40.0 m wide. if the average depth of water is 3.30 ft, what is the mass (in kg) of water in the pool?

Answer 1

The mass (in kg) of water in the pool is 1.264 $*$ $10^6$ kg.

What is mass?

A numerical measurement of inertia, a basic characteristic of all matter, in physics. It essentially refers to a body of matter's resistance to changing its speed or location in response to the application of a force. The change caused by an applied force is smaller the more mass a body has.

Mass is a physical body's total amount of matter. Inertia, or the body's resistance to acceleration when a net force is applied, is also measured by this term. The strength of an object's gravitational pull to other bodies is also influenced by its mass. The kilogram serves as the SI's fundamental mass unit.

Given: A pool is 31.4 m long and 40.0 m wide. if the average depth of water is 3.30 ft

31.4 $*$ 40.0 = 1256 $m^2$

1 m = 39.37 in = 3.28 ft

3.30 ft = 1.01 m

Volume of pool = 1256 $*$ 1.01 = 1264 $m^3$

Since 1 $m^3$ water contains $10^3 kg$ the volume of the pool is

1.264 E3 $*$ E3 = 1.264E6 kg

(or 1.264 $*$ $10^6$ kg)

The mass (in kg) of water in the pool is 1.264 $*$ $10^6$ kg.

To learn more about mass refer to:

brainly.com/question/19385703

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