Answer : The atomic weight of the element is, 121.75 amu
Explanation :
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:

As we are given that,
Mass of isotope 1 = 120.9038 amu
Percentage abundance of isotope 1 = 57.25 %
Fractional abundance of isotope 1 = 0.5725
Mass of isotope 2 = 122.8831 amu
Percentage abundance of isotope 2 = 100 - 57.25 = 42.75 %
Fractional abundance of isotope 2 = 0.4275
Now put all the given values in above formula, we get:
![\text{Average atomic mass of element}=\sum[(120.9038\times 0.5725)+(122.8831\times 0.4275)]](https://tex.z-dn.net/?f=%5Ctext%7BAverage%20atomic%20mass%20of%20element%7D%3D%5Csum%5B%28120.9038%5Ctimes%200.5725%29%2B%28122.8831%5Ctimes%200.4275%29%5D)

Therefore, the atomic weight of the element is, 121.75 amu
Answer:
Explanation:
area of loop = 6.3 x 10⁻⁴ m²
Total flux ( initial )
nB A
= 150 x .06 x 6.3 x 10⁻⁴
Final magnetic flux
150 x .03 x 6.3 x 10⁻⁴
change in flux
150 x .06 x 6.3 x 10⁻⁴ - 150 x .03 x 6.3 x 10⁻⁴
= 28.35 x 10⁻⁴ Weber .
b ) voltage induced = rate of change of flux
= change in flux / time
= 28.35 x 10⁻⁴ / 15 x 10⁻³
= 1.89 x 10⁻¹ V
c )
current induced = voltage induced / resistance
= 1.89 x 10⁻¹ / 4
= .4725 x 10⁻¹ A
= 47.25 m A .
I would say that sand in water is a suspension as you can see the particles with the naked eye or a microscope. Also, the solution will settle if left alone and the sand will sink to the bottom.
Answer:
Mechanical Energy (initial) = Mechanical energy (final)
Ep(initial) + Ek(initial) = Ep(final) + Ek(final)
mgh(initial) + 1/2mv²(initial) = mgh(final) + 1/2mv²(final)
m being the mass of the penguin (kg)
g being gravitational acceleration (9.80 m/s²)
v(initial) being zero
h(final) being zero,i.e. final height is zero
v(final) being final velocity
solve for h(initial) being initial height at the top of the glacier
answer will be in metres
NB: don't forget to square the velocity
Explanation:
Since they mentioned frictionless, we know that this is a closed system therefore we are free to use this equation of conservation of mechanical energy
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