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timofeeve [1]
2 years ago
7

Allotropes are different molecular forms of an element, such as dioxygen (O₂) and ozone (O₃). (b) Calculate the ratio of densiti

es, d₀₃/d₀₂, and explain the significance of this number.
Chemistry
1 answer:
kipiarov [429]2 years ago
4 0

The ratio of densities, d₀₃/d₀ is 3:2

We know that at STP all gas have the same volume that is $22.4 \mathrm{~L}$.

Dioxygen $1 \mathrm{mLe} \mathrm{O}_{2}=32 \mathrm{gm} / \mathrm{moL} .$

Ozone 1 mole  $\mathrm{O}_{3}=48 \mathrm{gm} / \mathrm{mol}$.

$\begin{aligned} \therefore \text { density of } \mathrm{O}_{2} \text { at STP } &=\frac{\text { mass of } \mathrm{O}_{2}}{\text { volume }} \\ \text { or, } d_{\mathrm{O}_{2}} &=\frac{32 \mathrm{gm} / \mathrm{mol}_{\mathrm{o}}}{22.4 \mathrm{~L}} \end{aligned}$

$\therefore$The ratio of densities,

$\frac{d_{3}}{d o_{2}}=\frac{\frac{48 \mathrm{gm} / \mathrm{mol}}{22.4 \mathrm{~L}}}{\frac{32 \mathrm{gm} / \mathrm{mol}}{22.4 \mathrm{~L}}}$

$\frac{d 0_{3}}{d 0_{2}}=\frac{3}{2}$

do3: do2 = 3:2

Oxygen is found naturally as a molecule. two oxygen atoms strongly bind together with a covalent double bond to shape dioxygen or O2. Oxygen is normally observed as a molecule. it is referred to as dioxygen.

After hydrogen and helium, oxygen is the third most plentiful element in the universe and the most established element in the world. two atoms of the factors combine to generate dioxygen, an odourless and colourless diatomic gasoline with the formulation O2, at ordinary temperature and stress.

Learn more about dioxygen brainly.com/question/19905677

#SPJ4

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Answer:

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Which of the following combinations of mass number and neutrons are possible as isotopes of astatine? Choose one or more:

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iv) A = 207, n = 122

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Explanation:

The mass number is the sum of the number of protons and the number of neutrons in an atom.A=no.of protons+no.of neutrons\\=>no.of neutrons=A-no.of protons\\

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Answer:

We should add 15.15 grams of ethylen glycol.

Explanation:

Step 1: Data given

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The boiling point elevation constant, Kbp, for water is 0.5121 °C/m

Step 2: Calculate mass needed

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Mass of ethylen glycol = 15.15 grams

We should add 15.15 grams of ethylen glycol.

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