<span>[Cu(NH3)4]2+ forms a blue solution. When concentrated HCl is added to this solution, what color will the solution change to yellow.
Reason:
When conc. HCl is added to the solution containing </span>[Cu(NH3)4]2+, Cl- ions will replace NH3 and form [Cu(Cl)4]2- complex. This can be understood for the following reaction:
[Cu(NH3)4]2+ + Cl- ↔ [Cu(Cl)4]2- + NH3
The Cl- ion is a weak field ligand, while NH3 is a strong field ligand. Hence, Cl- will in less splitting of d-orbitals, as compared to NH3. Due to this, photons of different energies will be absorbed by these complexes, and hence they display different colours.
Just use a solubility chart! Find the cation on the far left and the anion on the top and find where they connect. If it says "s," it is not soluble. If it says "aq," it is soluble. Here, ZnF (Zinc Fluoride) is soluble. Hope that helps! :)
P.S. Not all of the compounds above are on this particular chart. In future problems, just google "solubility chart" until you find one with all of the compounds you need to look at.
1 mol ------- 6,02·10²³
X ------------ 3,98·10²³
X = 3,98·10²³/<span>6,02·10²³
<u>X= 0,6611</u> moles of oxygen
________________________
:)</span>
Hey there!:
Given the reaction:
NaBr ⇌ Na⁺ + Br⁻
↓ ↓ ↓
0.150M 0.150M 0.150M
AgBr ⇌ Ag⁺ + Br⁻
↓ ↓ ↓
x x 0.150M
Therefore:
Ksp = x * 0.150
x = ( 7.7 * 10⁻¹³ ) / 0.150
x = 5.1 * 10⁻¹²
Answer B
Hope that helps!
