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2 years ago

Calculate each of the following: (b) Mass % of Mn in potassium permanganate

1 answer:

3 0

Mass percent is the estimation of the mass of the element in a compound in percentage form. The mass % of manganese (Mn) in potassium permanganate is 34.76 %.

<h3>What is the mass percentage?</h3>

The mass percentage is defined by dividing the mass of the element by the molecular mass of the compound followed by multiplying it by 100%. It is given as,

Mass % = (Atomic Mass of element ÷ Molecular Mass) × 100

As it is known that,

Atomic Mass of manganese = 54.94 g/mol

Molecular Mass of potassium permanganate = 158.034 g/mol

Substituting values to calculate mass % as:

% Mn = (Atomic Mass of Mn ÷ Molecular Mass of KMnO₄) × 100

= (54.94 g/mol ÷ 158.034 g/mol) × 100

= 34.76 %

Therefore, 34.76% Mn is present in KMnO₄.

Learn more about mass percentage, here:

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Calculate the number of pounds of CO2CO2 released into the atmosphere when a 22.0 gallon22.0 gallon tank of gasoline is burned i

Gnesinka [82]

Answer:

391.28771 pounds of carbon-dioxide was released into the atmosphere when 22.0 gallon tank of gasoline is burned in an automobile engine.

Explanation:

Density of the gasoline ,d= 0.692 g/mL

Volume of gasoline in an tanks,V = 22.0 gallons = 83,279.02 mL

Let mass of the gasoline be M

$Density= \frac{Mass}{Volume}$

M = V × d = 83,279.02 mL × 0.692 g/mL=57,629.081 g

Given that gasoline is primarily octane.

$2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O$

Mass of octane burnt in the tank = M = 57,629.081 g

Moles of octane = $\frac{57,629.081 g}{114.08g/mol}=505.1637 mol$

According to reaction, 2 moles of octane gives 16 moles of carbon-dioxide.

Then 505.1637 mol of octane will give:

$\frac{16}{2}\times 505.1637 mol=4,041.3100 mol$ of carbon-dioxide

Mass of 4,041.3100 mol of carbon-dioxide:

4,041.3100 mol × 44.01 g/mol = 177,858.05 g

Mass of carbon-dioxide produced in pounds = 391.28771 pounds

391.28771 pounds of carbon-dioxide was released into the atmosphere when 22.0 gallon tank of gasoline is burned in an automobile engine.

3 0

3 years ago

Question 1 of 10

SVETLANKA909090 [29]

Answer:

AS THE HYPOTHESIS MEANS THAT OUR THOUGHTS AND FINDINGS SO

PART B .... RATTLESNAKES VENOM CAN BE USED AS TREATMENT

Explanation:

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3 years ago

When 3.0g of magnesium is burnt in 2.00g of oxygen, 5.00g of magnesium oxide is produced. What mass of magnesium oxide will be f

guajiro [1.7K]

Answer: -

8.00 g

The law of conservation of mass

Explanation: -

When magnesium burns in air it combines with oxygen to form magnesium oxide.

The mass of the product is the mass of the magnesium oxide.

The mass of the reactant is the mass of the magnesium + mass of the oxygen.

Since matter cannot be created or destroyed according to the law of conservation of mass,

Mass of Magnesium oxide formed = mass of magnesium reacted + mass of oxygen reacted

= 3.00 g + 5.00 g

= 8.00 g

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3 years ago

If a gas displays a solubility of 0.00290M at a partial pressure of 125 kPa, what is the proportionality constant for this gas i

alexgriva [62]

Answer:

The proportionality constant ( Henry’s constant) = 2.32 * 10^-5 M/kPa

Explanation:

Here in this question, we are concerned with calculating the proportionality constant for this gas.

Mathematically, we can get this from Henry law

From Henry law;

Concentration = Henry constant * partial pressure

Thus Henry constant = concentration/partial pressure

Henry constant = 0.00290 M/125 kPa = 2.32 * 10^-5 M/kPa

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3 years ago

The isotope carbon-14 decays over time into nitrogen-14 with a half-life of 5,730 years. Suppose that you find a fossil that con

KATRIN_1 [288]

Answer:

11460 years

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0.693/t1/2 = 2.303/t log (No/N)

t1/2 = half life of the carbon

t = age of the fossil

No= amount of radioactive material originally present

N= amount of radioactive material present at time=t

No= mass of carbon + nitrogen = 5g

0.693/5730 = 2.303/t log (5/1.25)

1.21 ×10^-4 = 1.3866/t

t= 1.3866/1.21 ×10^-4

t= 11460 years

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3 years ago