Answer:
a star is like the sun a burning ball of gas that gives light to the outer space.
Explanation:
Answer:
0.1472 mol/L is the concentration of the barium hydroxide solution.
Explanation:

Mass of potassium hydrogen phthalate = 2.050 g
Molar mass of potassium hydrogen phthalate = 
According to reaction , 2 moles of potassium hydrogen phthalate reacts with 1 mole of barium hydroxide, then 0.01004 moles of potassium hydrogen phthalate will :
of barium hydroxide
Moles of barium hydroxide = 0.005020 mol
Volume of the barium hydroxide solution = 34.10 mL = 0.03410 L
1 mL = 0.001 L

Molarity of the barium hydroxiude silution :

0.1472 mol/L is the concentration of the barium hydroxide solution.
D IS THE ANSWER TO YOUR QUESTION
For this problem, we use Graham's Effusion Law to find out the rate of effusion of chlorine gas. The formula is as follows:
R₁/R₂ = √(M₂/M₁)
Let 1 be N₂ while 2 be Cl₂
255/R₂ = √(28/70.8)
Solving for R₂,
R₂ = 405.5 s
<em>Thus, it would take 405.5 s to effuse chlorine gas.</em>