Answer:
The answer is C.
Step-by-step explanation:
Answer:
A. Acute and B. Equilateral
Step-by-step explanation:
Answer:
10
Step-by-step explanation:
If we plug in any negative number as x, the result will always be greater than 4, which rules out answers A and B
lets try plugging in 4 as x to test answer C:
2(8-4)
2(4)= 8
8 is greater than 4, therefore C is wrong.
Lets try 10 as X (answer D):
2(8-10)
2(-2)
-4
We know that -4 is less than 4, therefore it makes the inequality true! :)
The area bounded by the 2 parabolas is A(θ) = 1/2∫(r₂²- r₁²).dθ between limits θ = a,b...
<span>the limits are solution to 3cosθ = 1+cosθ the points of intersection of curves. </span>
<span>2cosθ = 1 => θ = ±π/3 </span>
<span>A(θ) = 1/2∫(r₂²- r₁²).dθ = 1/2∫(3cosθ)² - (1+cosθ)².dθ </span>
<span>= 1/2∫(3cosθ)².dθ - 1/2∫(1+cosθ)².dθ </span>
<span>= 9/8[2θ + sin(2θ)] - 1/8[6θ + 8sinθ +sin(2θ)] .. </span>
<span>.............where I have used ∫(cosθ)².dθ=1/4[2θ + sin(2θ)] </span>
<span>= 3θ/2 +sin(2θ) - sin(θ) </span>
<span>Area = A(π/3) - A(-π/3) </span>
<span>= 3π/6 + sin(2π/3) -sin(π/3) - (-3π/6) - sin(-2π/3) + sin(-π/3) </span>
<span>= π.</span>
