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ExtremeBDS [4]
3 years ago
13

Classify the elements as diatomic or monatomic. If necessary, refer to the periodic table to help you identify the diatomic elem

ents.
carbon

helium

hydrogen

iodine

oxygen

sodium

​

Chemistry
2 answers:
Oksanka [162]3 years ago
6 0

Answer:

Carbon: Monatomic

Helium: Monatomic

Hydrogen: Diatomic

Iodine: Diatomic

Oxygen: Diatomic

Sodium: Monatomic

Explanation:

There you go

gladu [14]3 years ago
3 0

Answer:

carbon- monatomic

helium- monatomic

hydrogen- diatomic

iodine- diatomic

oxygen- diatomic

sodium- monatomic

Explanation:

the diatomic elements can be remembered with this sentence:

Have No Fear Of Ice Clear Brownies

have- hydrogen

no- nitrogen

fear- fluorine

of- oxygen

ice- iodine

clear- chlorine

brownies- bromine

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A flask contains methane, chlorine and carbon monoxide gases. the partial pressures of each are 0.215 atm, 0.066 atm, and 0.826
hjlf

Answer;

The total pressure is 1.107 atm.

Explanation;

The total pressure is the sum of the pressures of the three gases in the flask

Pressure (total) = 0.215 atm + 0.066 atm + 0.826 atm = 1.107 atm

= 1.107 atm.

8 0
3 years ago
Read 2 more answers
What is biopolymer ?​
Greeley [361]

Answer:

Biopolymers are natural polymers produced by the cells of living organisms. Biopolymers consist of monomeric units that are covalently bonded to form larger molecules. There are three main classes of biopolymers, classified according to the monomers used and the structure of the biopolymer formed: polynucleotides, polypeptides, and polysaccharides.

Explanation:

5 0
3 years ago
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Each molecule of lycopene contains 40 atoms of carbon (plus other atoms). The mass percent of carbon in lycopene is 84.49%. What
IrinaK [193]

Answer: 568g/mol

Explanation:

It should be noted that there are 40 atoms of carbon in lycopene.

Since mass of 1 carbon = 12g/mol

Mass of 40 carbon atoms = 40 × 12g/mol = 480g/mol

Let the molar mass of lycopene be represented by x.

Therefore the molar mass of carbon = x × mass percent of carbon in lycopene

x × 84.49% = 480g/mol

x × 0.8449 = 480g/mol

x = 480/0.8449

x = 568g/mol

The molar mass of lycopene is 568g/mol

5 0
2 years ago
Put the steps of the carbon cycle in order using Step 1 as your starting point. Step 1: Bacteria, through nitrogen fixation and
Amanda [17]

Answer:

The answer is explained below

Explanation:

Put the steps of the carbon cycle in order using Step 1 as your starting point

Step 1: Bacteria, through nitrogen fixation and nitrification, convert nitrogen into a usable form. The animal dies and decomposes, returning nitrogen back to the soil. Once nitrogen is in usable form, it is taken up by plants and assimilated into proteins.. An animal eats a plant and the nitrogen becomes part of the animal’s proteins.

The steps taking in the carbon circle using step 1 as the starting point is as follows:

Step 1:  Bacteria, through nitrogen fixation and nitrification, convert nitrogen into a usable form.

Bacteria convert nitrogen into nitrites and nitrates through the process of nitrification. Nitrites and nitrates are in the form that can be used by the plants

Step 2: Once nitrogen is in usable form, it is taken up by plants and assimilated into proteins.

The Nitrogen can only be used by the plants when in nitrites and nitrates form. When in this form, it is then assimilated into plant tissue as protein.

Step 3: An animal eats a plant and the nitrogen becomes part of the animal’s proteins.

An animal such as rabbit eats the plant and the protein in the plant becomes protein in the animal.

Step 4: The animal dies and decomposes, returning nitrogen back to the soil.

When the animal dies, the animal undergoes decomposition and the nitrogen in the animal is returned to the soil

5 0
3 years ago
9. Suppose that 25.0 mL of a gas at 725 mm Hg and 20°C is converted to standard
storchak [24]

Answer:

V₂ = 22.23 mL

Explanation:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

Given data:

Initial volume = 25 mL

Initial pressure = 725 mmHg (725/760 =0.954 atm)

Initial temperature = 20 °C (20 +273 = 293 K)

Final pressure = standard = 1 atm

Final temperature = standard = 273.15 K

Final volume = ?

Solution:

P₁V₁/T₁ = P₂V₂/T₂

V₂ = P₁V₁ T₂/ T₁  P₂

V₂ = 0.954 atm × 25 mL × 273.15 K / 293 K × 1 atm

V₂ =  6514.63 mL . atm . K  / 293 K . atm

V₂ = 22.23 mL

8 0
2 years ago
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