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Scorpion4ik [409]
2 years ago
10

A gaseous mixture of 10.0 volumes of CO₂, 1.00 volume of unreacted O₂, and 50.0 volumes of unreacted N₂ leaves an engineat 4.0 a

tm and 800. K. Assuming that the mixture reaches equilibrium, what are (b) the concentration (in picograms per liter, pg/L) of CO in this exhaust gas?2CO₂(g) ⇄ 2CO(g) + O₂(g) Kp = 1.4×10⁻²⁸ at 800K(The actual concentration of CO in exhaust gas is much higher because the gases do not reach equilibrium in the short transit time through the engine and exhaust system.)
Chemistry
1 answer:
ycow [4]2 years ago
3 0

The masses of CO and CO2​ are 90.55g and 100−90.55=9.45 g respectively.

<h3>Total mass.</h3>

Let the mixture has 100g as total mass.

The number of moles of CO is 2890.55​=3.234.

The number of moles of CO2​ is 449.45​=0.215.

The mole fraction of CO is 3.234+0.2153.234​=0.938.

The mole fraction of CO2​ is 1−0.938=0.062.

The partial pressure of CO is the product of the mole fraction of CO and the total pressure.

It is 0.938×1=0.938 atm.

The partial pressure of carbon dioxide is 0.062×1=0.042 atm.

The expression for the equilibrium constant is:

Kp​=PCO2​​PCO2​​=0.062(0.938)2​=14.19

Δng​=2−1=1

Kc​=Kp​(RT)−Δn=14.19×(0.0821×1127)−1=0.153.

To learn more about equilibrium constant visit the link

brainly.com/question/15118952

#SPJ4

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B. velocity

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100 °C, because it is the boiling point of water.

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Can someone please help me with my homework ASAP? It's due tonight.
sladkih [1.3K]

Answer:

27.7 grams of Li

0.140 moles of Co

0.158 moles of K

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Explanation:

Mass / Molar mass = Mol

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3.99 m . 6.94 g/m = 27.7 grams of Li

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0.8 mol . 74.92 g/m = 59.9 grams of As

6.02x10²³ (NA) particles are contained in 1 mol

6.02x10²³ are contained in 1 mol U____ 1 mol  H ____ 1 mol O ___ 1 mol Pb

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8.60x10²⁵atoms H  ____ 8.60x10²⁵ / 6.02x10²³  = 142.8 moles of H

1.20x10²² atoms O  ____ 1.20x10²² / 6.02x10²³ = 0.0199 moles of O

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3 years ago
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The answer to your question is Protons = 36, Neutrons = 26, Electrons = 36

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                                ⁷⁰Se²⁻

The number of protons is equal to the atomic number, Selenium has an atomic number of 34. Then the number of protons = 34.

The number of neutrons = Mass number - number of protons

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The number of electrons = number of protons + 2 because of the 2- next to the symbol of Selenium.

Number of electrons = 34 + 2

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