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Scorpion4ik [409]
2 years ago
10

A gaseous mixture of 10.0 volumes of CO₂, 1.00 volume of unreacted O₂, and 50.0 volumes of unreacted N₂ leaves an engineat 4.0 a

tm and 800. K. Assuming that the mixture reaches equilibrium, what are (b) the concentration (in picograms per liter, pg/L) of CO in this exhaust gas?2CO₂(g) ⇄ 2CO(g) + O₂(g) Kp = 1.4×10⁻²⁸ at 800K(The actual concentration of CO in exhaust gas is much higher because the gases do not reach equilibrium in the short transit time through the engine and exhaust system.)
Chemistry
1 answer:
ycow [4]2 years ago
3 0

The masses of CO and CO2​ are 90.55g and 100−90.55=9.45 g respectively.

<h3>Total mass.</h3>

Let the mixture has 100g as total mass.

The number of moles of CO is 2890.55​=3.234.

The number of moles of CO2​ is 449.45​=0.215.

The mole fraction of CO is 3.234+0.2153.234​=0.938.

The mole fraction of CO2​ is 1−0.938=0.062.

The partial pressure of CO is the product of the mole fraction of CO and the total pressure.

It is 0.938×1=0.938 atm.

The partial pressure of carbon dioxide is 0.062×1=0.042 atm.

The expression for the equilibrium constant is:

Kp​=PCO2​​PCO2​​=0.062(0.938)2​=14.19

Δng​=2−1=1

Kc​=Kp​(RT)−Δn=14.19×(0.0821×1127)−1=0.153.

To learn more about equilibrium constant visit the link

brainly.com/question/15118952

#SPJ4

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15 grams for the drug powder
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3 years ago
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When a 0. 1 m aqueous solution of hydrocyanic acid, hcn, reaches equilibrium, the ph is measured to be 5. 20. using this informa
Sav [38]

When a 0. 1 m aqueous solution of hydrocyanic acid, HCN, reaches equilibrium, the ka for hydrocyanic acid is  3.969 x 10⁻¹⁰.

<h3>What is ka value?</h3>

It's the value of equilibrium constant for the dissociation of ions into a solution. The more the Ka value the more will be dissociation.

Ka = [H₃O⁺]² / [HCN] [H₃O⁺]

The pH is 5.20

-log [H₃O⁺] = 5.20

Putting antitlog both side.

The value will be 6.30 x 10⁻⁶

Ka = (6.30 x 10⁻⁶)²  / 0.1 - 6.30 x 10⁻⁶

0.1 - 6.30 x 10⁻⁶ = 0.1

Ka = 3.969 x 10⁻¹⁰

Thus, the Ka value for hydrocyanic acid is 3.969 x 10⁻¹⁰.

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brainly.com/question/2796803

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7 0
2 years ago
A sample initially contained 150 mg of radon-222. After 11.4 days only 18.75mg of the radon-222 in the sample remained. How many
beks73 [17]

<u>Answer: </u>

A sample initially contained 150 mg of radon-222. After 11.4 days only 18.75mg of the radon-222 in the sample remained where 3 half-lives have passed

<u>Explanation:</u>

Given, the initial value of the sample, A_0 = 150mg

Final value of the sample or the quantity left, A = 18.75mg

Time = 11.4 days

The amount left after first half life will be ½.

The number of half-life is calculated by the formula

\frac{A}{A_{0}}=\left(\frac{1}{2}\right)^{N}

where N is the no. of half life

Substituting the values,

\frac{18.75}{150}=\left(\frac{1}{2}\right)^{N}

\left(\frac{1}{2}\right)^{3}=\left(\frac{1}{2}\right)^{N}

On equating, we get, N = 3

Therefore, 3 half-lives have passed.

7 0
3 years ago
Question 1 (True/False Worth 2 points) (04.03 LC) When Pb and AlCl3 react together, lead (Pb) can replace aluminum (Al) in the c
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Answer:

For 1: The correct answer is false.

For 2: The correct answer is Na_3PO_4+3KOH\rightarrow 3NaOH + K_3PO_4, because K retains the same charge throughout the reaction.

For 3: The correct answer is Zn+H_2SO_4\rightarrow ZnSO_4 + H_2

For 4: The correct answer is a single replacement reaction takes place because sodium is more reactive than hydrogen.

For 5: The correct answer is False.

For 6: The correct answer is it is a single replacement reaction, and the cations in the two ionic compounds are different.

Explanation:

  • <u>For 1: </u>

This type or reaction is based on the reactivity series. If the metal which lies above in the series will replace the metal which lies below in the series easily.

From the reactivity table attached below, we know that lead lies below in the series to Aluminium and hence, it will not replace in the reaction.

Pb+AlCl_3\rightarrow \text{No reaction}

Hence, the correct answer is False.

  • <u>For 2: </u>

A balanced equation is defined as the equation in which there are same number of atoms present on the reactant side and the product side.

The balanced equation always follow Law of Conservation of Mass.

So, from the given options, the below equation is the balanced equation because K retains the same charge throughout the reaction.

Na_3PO_4+3KOH\rightarrow 3NaOH + K_3PO_4

  • <u>For 3:</u>

A single displacement reaction is a type of chemical reaction in which one element replaces another element in a chemical reaction. The element which is more reactive will replace the less less reactive element.

This is explained by reactivity series as the metal which lies above in the series will replace the metal which lies below in the series easily. From the given equations, the equation which is a type of single displacement reaction is:

Zn+H_2SO_4\rightarrow ZnSO_4 + H_2

Ba(OH)_2+H_2SO_4\rightarrow BaSO_4 + 2H_2O : This equation is a type of double displacement reaction.

2Mg+O_2\rightarrow 2MgO  : This equation is a type of combination reaction.

H_2O+CO_2\rightarrow H_2CO_3 : This equation is a type of combination reaction.

  • <u>For 4:</u>

A single displacement reaction is a type of chemical reaction in which one element replaces another element in a chemical reaction.

A+BC\rightarrow AC+B

A double displacement reaction is a type of chemical reaction in which exchange of ins takes place.

AB+CD\rightarrow AD+BC

In the question, it is asked that sodium metal is reacting with water to produce hydrogen gas and sodium hydroxide. This reaction is a type of single displacement reaction because sodium is more reactive than hydrogen as shown in the reactivity series.

2Na+2H_2O\rightarrow H_2+2NaOH

  • <u>For 5: </u>

A single displacement reaction is a type of chemical reaction in which one element replaces another element in a chemical reaction. This reaction will not follow when an element replaces similar element.

Hence, the statement is False.

  • <u>For 6:</u>

For the reaction:

\text{Metal + Ionic compound}\rightarrow \text{Metal + Ionic compound}

It is a type single replacement reaction as the cations in the two ionic compounds are different.

For Example:

3Na+AlCl_3\rightarrow 3NaCl+Al

Where, Sodium and Aluminium are the cations and chlorine is an anion.

6 0
4 years ago
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Answer: 3.427 X 10 3 TIMES AND 4.56 X 10 3 TIMES

Explanation:

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