All categories

3 years ago

15. What is true about concentration of a solution? *

Chemistry

1 answer:

Naya [18.7K]3 years ago

8 0

<h3>Answer:</h3>

A saturated solution is a chemical solution containing the maximum concentration of a solute dissolved in the solvent.

<h3>Explanation:</h3>

A solution is made by dissolving a solute in a solvent.
For example dissolving a salt in a solvent such as water results to a solution.
Solution may either be saturated or unsaturated.
Unsaturated solution is a solution that can dissolve more solute upon addition because it has not reached saturation.
A saturated solution on the other hand is a solution that has maximum solute and the concentration of solute is maximum and thus the solvent can not dissolve any more solute.
Therefore, a saturated solutions contain maximum concentration of a solute dissolved in the solute.

You might be interested in

What Is Chemical Equilibrium?a. When all reactants turn into products, the chemical reaction reaches equilibrium. c. Reactants a

Gnoma [55]

Answer:

The correct answer is <em>d. At equilibrium, the forward reaction and reverse reaction will have the same reaction rate.</em>

Explanation:

When a reaction begins, the reactants combine to form products. At the same time of product formation, the convertion of products into reactants also occur. The reaction reaches <em>chemical equilibrium </em>when the rate of forward reaction (the convertion of reactant into products) is equal to the rate of reverse reaction (the convertion of product into reactants). Upon this state, the concentration of reactants and products do not change in time (that does not mean that the concentration of reactants and products are equal, but that once the chemical equilibrium is reached, their concentrations at this point will not vary with the time because the forward and reverse reactions are occuring at the same velocity).

3 0

3 years ago

Using the mmoles of (35)-2,2,-dibromo-3,4-dimethylpentane calculated earlier and the molecular weight of the product (962 g/mol)

Sedbober [7]

Answer:

The yield of the product in gram is $\mathsf{{w_P}=0.26 \ gram}$

Explanation:

Given that:

the molecular mass weight of the product = 96.2 g/mol

the molecular mass of the reagent (3S)-2,2,-dibromo-3,4-dimethylpentane is 257.997 g

given that the millimoles of the reagent = 2,7 millimoles = $2.7 \times 10^{-3} \ moles$

We know that:

Number of moles = mass/molar mass

Then:

$2.7 \times 10^{-3} = \dfrac{ mass}{257.997}$

$mass = 2.7 \times 10^{-3} \times 257.997$

mass = 0.697

Theoretical yield = (number of moles of the product/ number of moles of reactant) × 100

i.e

Theoretical yield = $\dfrac{n_P}{n_R}\times 100\%$

where;

$n_P = \dfrac{w_P}{m_P}$ and $n_R = \dfrac{w_R}{m_R}$

Theoretical yield = $\dfrac{(\dfrac{w_P}{m_P})}{(\dfrac{w_R}{m_R})} \times 100\%$

Given that the theoretical yield = 100%

Then:

$100\% =\dfrac{(\dfrac{w_P}{m_P})}{(\dfrac{w_R}{m_R})} \times 100\%$

$\dfrac{w_P}{m_P}=\dfrac{w_R}{m_R}$

${w_P}=\dfrac{w_R \times m_P}{m_R}$

where,

$w_P$ = derived weight of the product

$m_P =$ the molecular mass of the derived product

$m_R =$ the molecular mass of the reagent

$w_R$ = weight in a gram of the reagent

${w_P}=\dfrac{w_R \times m_P}{m_R}$

${w_P}=\dfrac{0.697 \times 96.2}{257.997}$

$\mathsf{{w_P}=0.26 \ gram}$

8 0

3 years ago

The oxidation number of Na in NaCl a. 0 b. -1 c. +1 d. -2 e. +2

Dahasolnce [82]

NaCl:

Na = + 1

Cl = - 1

hope this helps!

4 0

3 years ago

True or false? Balanced forces cause a change in motion. <br> How do you know this?

Nat2105 [25]

Answer:

false

Explanation:

Balanced forces do not change the motion of an object. The motion of an object will not change if the forces pushing or pulling the object are balanced.

6 0

3 years ago

Read 2 more answers

A mixture of gases contains 4.46 moles of neon (Ne), 0.74 mole of argon (Ar), and 2.15 moles of xenon (Xe). Calculate the partia

viva [34]

Explanation:

The partial pressure of an individual gas is equal to the total pressure of the mixture multiplied by the mole fraction of the gas.

Total pressure = 2atm

Mole Fraction = number of moles / total number of moles

Neon

Mole Fraction = 4.46 / 7.35 = 0.607

Partial Pressure = 0.607 * 2 = 1.214 atm

Argon

Mole Fraction = 0.74 / 7.35 = 0.101

Partial Pressure = 0.101 * 2 = 0.202 atm

Xenon

Mole Fraction = 2.15 / 7.35 = 0.293

Partial Pressure = 0.293 * 2 = 0.586 atm

5 0

3 years ago