Answer:
The answer to your question is:
Explanation:
Other sugars with the same chemical formula as Glucose:
Sugar Formula Description
Glucose C₆H₁₂O₆ It's the most abundant monosaccharide.
Mannose C₆H₁₂O₆ It's found in plants and some animals.
Fructose C₆H₁₂O₆ It's the sugar of fruits.
Galactose C₆H₁₂O₆ It's found in milk.
We can set up an ICE table for the reaction:
HClO H+ ClO-
Initial 0.0375 0 0
Change -x +x +x
Equilibrium 0.0375-x x x
We calculate [H+] from Ka:
Ka = 3.0x10^-8 = [H+][ClO-]/[HClO] = (x)(x)/(0.0375-x)
Approximating that x is negligible compared to 0.0375 simplifies the equation to
3.0x10^-8 = (x)(x)/0.0375
3.0x10^-8 = x2/0.0375
x2 = (3.0x10^-8)(0.0375) = 1.125x10^-9
x = sqrt(1.125x10^-9) = 0.0000335 = 3.35x10^-5 = [H+]
in which 0.0000335 is indeed negligible compared to 0.0375.
We can now calculate pH:
pH = -log [H+] = - log (3.35 x 10^-5) = 4.47
Answer:
What percent of physically assaulted or abused adolescents reported lifetime substance abuse or dependence? Select one:
d. 25 percent
Explanation:
The study performed at the National Institute of Justice in 2003, called "Youth Victimization: Prevalence and Implications", Washington, D.C., U.S. Department of Justice, showed a rate of lifetime substance abuse or dependence at approximately 25 percent for adolescents who had been physically assaulted or abused. This compares to a rate of approximately six percent for adolescents who had not been physically assaulted or abused.
A solution that appears dark orange in color is not absorbing all orange wavelengths of light.
Answer:
Explanation:
Moles of SO₃ = 0.760 mol
Volume = 1.50 L
[SO₃] = 0.5067 M
Considering the ICE table for the equilibrium as:
Given:
Equilibrium concentration of O₂ = 0.130 mol
Volume = 1.50 L
[O₂] = x = 0.0867 M
[SO₂] = 2x = 0.1733 M
[SO₃] = 0.5067-2x = 0.3334 M
The expression for the equilibrium constant is:
![K_c=\frac {[SO_2]^2[O_2]}{[SO_3]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%20%7B%5BSO_2%5D%5E2%5BO_2%5D%7D%7B%5BSO_3%5D%5E2%7D)
