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2 years ago

[OU.04] The picture below shows two galaxies. What of these statements best describes a similarity between the two galaxies?

Physics

2 answers:

Vitek1552 [10]2 years ago

7 0

Answer:

Explanation: Both have shapes determined by gravitational forces.

natima [27]2 years ago

3 0

Answer: Option (D)

Explanation: A galaxy is considered to be a large and extensive body comprised of the interstellar dust particles, dark matter and variable gases. The above mentioned particles are attached with one another forming variable shapes and are all held by the gravitational force. Gravity is the main factor responsible for the existence of this galaxies.

This is the reason, why the different shaped galaxies exist in the vast space, maintaining some similarity with one another.

Thus the correct answer is Option (D).

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2 years ago

Jake calculates that the frequency of a wave is 230 hertz, and its wave is moving at 460 m/s. What is the wavelength of the wave

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2 years ago

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2 years ago

Read 2 more answers

Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant

Elena L [17]

Answer:

19 m/s

Explanation:

The complete question requires the final speed to be calculated.

Velocity is the rate and direction at which an object moves. Acceleration is the rate of change of velocity per unit time and can be calculated by the difference in velocity over a given time.

For this question, first the unknown acceleration must be calculated and used to determine the final velocity

Step 1: Calculate the acceleration

$a=\frac{v_{2}-v{1}}{t_{1}}$

$a=\frac{11-7}{8}$

$a=\frac{4}{8}$

$a=0.5 m/s^{2}$

Step 2: Calculate the velocity using the acceleration calculated above

$a=\frac{v_{3}-v{2}}{t_{2}}$

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2 years ago

An 7.5 × binocular has 3.7-cm-focal-length eyepieces. What is the focal length of the objective lenses? Express your answer to t

elixir [45]

To solve this problem we will apply the concept of magnification, which is given as the relationship between the focal length of the eyepieces and the focal length of the objective. This relationship can be expressed mathematically as,

$\mu = \frac{f_0}{f_e}$