Answer:
go to : www.planetresourses.com/test2.00/answers, ant type in that test name
Explanation:
yee
Wavelength = (speed) / (frequency) = (460 m/s) / (230/sec) = <em>2 meters</em>
Answer:
19 m/s
Explanation:
The complete question requires the final speed to be calculated.
Velocity is the rate and direction at which an object moves. Acceleration is the rate of change of velocity per unit time and can be calculated by the difference in velocity over a given time.
For this question, first the unknown acceleration must be calculated and used to determine the final velocity
Step 1: Calculate the acceleration
![a=\frac{v_{2}-v{1}}{t_{1}}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Bv_%7B2%7D-v%7B1%7D%7D%7Bt_%7B1%7D%7D)
![a=\frac{11-7}{8}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B11-7%7D%7B8%7D)
![a=\frac{4}{8}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B4%7D%7B8%7D)
![a=0.5 m/s^{2}](https://tex.z-dn.net/?f=a%3D0.5%20m%2Fs%5E%7B2%7D)
Step 2: Calculate the velocity using the acceleration calculated above
![a=\frac{v_{3}-v{2}}{t_{2}}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Bv_%7B3%7D-v%7B2%7D%7D%7Bt_%7B2%7D%7D)
![0.5=\frac{v_{3}-11}{16}](https://tex.z-dn.net/?f=0.5%3D%5Cfrac%7Bv_%7B3%7D-11%7D%7B16%7D)
![v_{3}=19 m/s](https://tex.z-dn.net/?f=v_%7B3%7D%3D19%20m%2Fs)
To solve this problem we will apply the concept of magnification, which is given as the relationship between the focal length of the eyepieces and the focal length of the objective. This relationship can be expressed mathematically as,
![\mu = \frac{f_0}{f_e}](https://tex.z-dn.net/?f=%5Cmu%20%3D%20%5Cfrac%7Bf_0%7D%7Bf_e%7D)
Here,
= Magnification
= Focal length eyepieces
= Focal length of the Objective
Rearranging to find the focal length of the objective
![f_0 = \mu f_e](https://tex.z-dn.net/?f=f_0%20%3D%20%5Cmu%20f_e)
Replacing with our values
![f_0 = 7.5* 3.7cm](https://tex.z-dn.net/?f=f_0%20%3D%207.5%2A%203.7cm)
![f_0 = 27.75cm](https://tex.z-dn.net/?f=f_0%20%3D%2027.75cm)
Therefore the focal length of th eobjective lenses is 27.75cm