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Veseljchak [2.6K]
3 years ago
14

Anyone can help?? I need it done before 9am please!!

Physics
1 answer:
Delicious77 [7]3 years ago
6 0

Answer:

The answer is below

Explanation:

The equation for a linear line graph is given by:

y = mx + b, where y and x are variables, m is the slope of the graph and b is the y intercept (that is value of y when x is zero).

The slope (m) of a line passing through two points (x_1,y_1)\ and\ (x_2,y_2) is given by:

m=\frac{y_2-y_1}{x_2-x_1}

A) The first line passes through the point (0, 0) and (10, 60). It is represented as (time, velocity). Hence the slope is:

m=\frac{60 -0}{10-0}=6\ m/min^2

B) The second line passes through the point (10, 60) and (15, 60). Hence the slope is:

m=\frac{60 -60}{15-10}=0\ m/min^2

C) The third line passes through the point (15, 60) and (40, -40). Hence the slope is:

m=\frac{-40 -60}{40-15}=-4\ m/min^2

D) The third line passes through the point (40, -40) and (55, 0). Hence the slope is:

m=\frac{0 -(-40)}{55-40}=2.67\ m/min^2

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Answer:

need Read this excerpt from "Not a Dove, But No Longer a Hawk."

Despite these misgivings, I do not see how we can do anything but continue to prosecute the war. We can and should limit the violence and the suffering being inflicted on the civilians as much as possible, but for whatever reasons, successive Administrations in Washington have carried the commitment in Vietnam to the point where it would be very difficult to prevent any precipitate retreat from degenerating into a rout. If the United States were to disengage from Vietnam under adverse conditions, I believe that the resulting political and psychological shockwaves might undermine our entire position in Southeast Asia.

Which statement best describes the paradox in this excerpt?

The author acknowledges that civilians should not suffer, but states that the civilians must retreat.

The author suggests that the administrators in Washington are busy making policies while overlooking the need to end the war.

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3 years ago
A 75.0 Ohm resistor uses 0.285 W of power. What is the voltage across the resistor?
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A student drops a rubber ball onto a surface. Assume that this is a closed system. The ball bounces, but each successive bounce
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An aluminum bar 600mm long, with diameter 40mm long has a hole drilled in the center of the bar.The hole is 30mm in diameter and
Svetradugi [14.3K]

Answer:

Total contraction on the Bar  = 1.22786 mm

Explanation:

Given that:

Total Length for aluminum bar = 600 mm  

Diameter for aluminum bar  = 40 mm

Hole diameter  = 30 mm

Hole length = 100 mm

elasticity for the aluminum is 85GN/m² = 85 × 10³ N/mm²

compressive load P = 180 KN = 180  × 10³ N

Calculate the total contraction on the bar = ???

The relation used in  calculating the contraction on the bar is:

\delta L = \dfrac{P *L }{A*E}

The relation used in  calculating the total contraction on the bar can be expressed as :

Total contraction in the Bar = (contraction in part of bar without hole + contraction in part of bar with hole)

i.e

Total contraction on the Bar = \dfrac{P *L_1 }{A_1*E} +  \dfrac{P *L_2 }{A_2 *E}

Let's find the area of cross section without the hole and with the hole

Area of cross section without the hole is :

Using A = πd²/4

A = π (40)²/4

A = 1256.64 mm²

Area of cross section with the hole is :

A = π (40²-30²)/4

A = 549.78 mm²

Total contraction on the Bar = \dfrac{P *L_1 }{A_1*E} +  \dfrac{P *L_2 }{A_2 *E}

Total contraction on the Bar  = \dfrac{180 *10^3 \N  }{85*10^3 \ N/mm^2} [\dfrac{500}{1256.64}+ \dfrac{100}{549.78}]

Total contraction on the Bar  = 2.117( 0.398 + 0.182)

Total contraction on the Bar  = 2.117*(0.58)

Total contraction on the Bar  = 1.22786 mm

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