Huhhhh this is confusing ummm hello I guess
Answer:
2 m/s²
Explanation:
Given:
v₀ = 0 m/s
v = 20 m/s
t = 10 s
Find: a
a = (v − v₀) / t
a = (20 m/s − 0 m/s) / 10 s
a = 2 m/s²
Answer:
The work done will be 
Explanation:
The work equation is given by:

Where:
F is the force due to gravity (weight = mg)
x is the length of the ramp (3 m)
Now, the force acting here is the component of weight in the ramp direction, so it will be:

Therefore, the work done will be:



I hope it helps you!
Missing figure: find it in attachment.
Answer:
Force D
Explanation:
In order to answer the question, let's keep in mind that the force of gravity on an object on Earth is the attractive force exerted by the Earth on the object; its direction is always downward (towards the Earth's centre), and its magnitude is given by
F = mg
where m is the mass of the object and g is the acceleration of gravity.
It follows immediately that in the figure, the force of gravity is the only force acting downward: therefore, force D.
The other forces are called:
Force A: thrust (it is the forward force generated by the engines)
Force B: lift (it is the upward produced by the aerodynamics of the wings)
Force C: air resistance (it is the backward force due to the friction between the air and the surface of the plane)
Answer:
Part 1)

Part 2)

Part 3)

Part 4)

Part 5)

Explanation:
Part a)
Initial angular momentum of the merry go round is given as

here we know that


now we have


Part b)
Angular momentum of the person is given as

so we have


R = 1.99 m
so we have


Part 3)
Angular momentum of the person is always constant with respect to the axis of disc
so it is given as

Part 4)
By angular momentum conservation of the system we will have




Part 5)
Force required to hold the person is centripetal force which act towards the center
so we will have


