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Orlov [11]
4 years ago
6

If your starting salary is $40,000 and you receive a 3% increase at the end of every year, what is the total amount, in dollars,

you will earn over the first 16 years that you work?
Mathematics
2 answers:
aniked [119]4 years ago
4 0

Answer:

If my starting salary is $40,000 and I receive a 3% increase at the end of every year, after 16 years of work, I will earn $64,188.25.

Step-by-step explanation:

Starting salary: $40,000

Year 1: $40,000 x 1.03 = $41,200

Year 2: $41,200 x 1.03 = $42,436

Year 3: $42,436 x 1.03 = $43,709.08

Year 4: $43,709.08 x 1.03 = $45,020.35

Year 5: $45,020.35 x 1.03 = $46,370.96

Year 6: $46,370.96 x 1.03 = $47,762.09

Year 7: $47,762.09 x 1.03 = $49,194.95

Year 8: $49,194.95 x 1.03 = $50,670.80

Year 9: $50,670.80 x 1.03 = $52,190.92

Year 10: $52,190.92 x 1.03 = $53,756.65

Year 11: $53,756.65 x 1.03 = $55,369.35

Year 12: $55,369.35 x 1.03 = $57,030.43

Year 13: $57,030.43 x 1.03 = $58,741.34

Year 14: $58,741.34 x 1.03 = $60,503.58

Year 15: $60,503.58 x 1.03 = $62,318.69

Year 16: $62,318.69 x 1.03 = $64,188.25

ss7ja [257]4 years ago
3 0

the equation would be 40000 x (1+.03)^16 = $64,188.26

 This is how much you will earn per year after 16 years.

 If you want to know the total over the 16 years ( that's the way your question is written) you would have to do that formula for all 16 years and add them all ( $870,463.50)

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4 0
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{:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div \bigg(10 - \overline{8 - 2 } \bigg)\bigg\} \bigg]}}}}

{:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div \bigg(10 - 6\bigg)\bigg\} \bigg]}}}}

<u>Simplifying parentheses brackets</u>

{:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div \bigg(10 - 6\bigg)\bigg\} \bigg]}}}}

{:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div 4\bigg\} \bigg]}}}}

<u>Simplifying curly brackets </u>

{:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div 4\bigg\} \bigg]}}}}

{:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{ \dfrac{16}{4} \bigg\} \bigg]}}}}

{:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{ \cancel{\dfrac{16}{4}} \bigg\} \bigg]}}}}

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KATRIN_1 [288]

Answer:

20. AB = 42

21. BC = 28

22. AC = 70

23. BC = 20.4

24. FH = 48

25. DE = 10, EF = 10, DF = 20

Step-by-step explanation:

✍️Given:

AB = 2x + 7

BC = 28

AC = 4x,

20. Assuming B is between A and C, thus:

AB + BC = AC (Segment Addition Postulate)

2x + 7 + 28 = 4x (substitution)

Collect like terms

2x + 35 = 4x

35 = 4x - 2x

35 = 2x

Divide both side by 2

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AB = 2x + 7

Plug in the value of x

AB = 2(17.5) + 7 = 42

21. BC = 28 (given)

22. AC = 4x

Plug in the value of x

AC = 4(17.5) = 70

✍️Given:

AC = 35 and AB = 14.6.

Assuming B is between A and C, thus:

23. AB + BC = AC (Segment Addition Postulate)

14.6 + BC = 35 (Substitution)

Subtract 14.6 from each side

BC = 35 - 14.6

BC = 20.4

24. FH = 7x + 6

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4x + 24 = 7x + 6 (substitution)

Collect like terms

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-3x = - 18

Divide both sides by -3

x = 6

FH = 7x + 6

Plug in the value of x

FH = 7(6) + 6 = 48

25. DE = 5x, EF = 3x + 4

Given that E bisects DF, therefore,

DE = EF

5x = 3x + 4 (substitution)

Subtract 3x from each side

5x - 3x = 4

2x = 4

Divide both sides by 2

x = 2

DE = 5x

Plug in the value of x

DE = 5(2) = 10

EF = 3x + 4

Plug in the value of x

EF = 3(2) + 4 = 10

DF = DE + EF

DE = 10 + 10 (substitution)

DE = 20

4 0
3 years ago
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