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pishuonlain [190]
2 years ago
15

Sorbitol, an artificial sweetener, has a formula of c9h14o6. what is the mass of one molecule of sorbitol?

Chemistry
1 answer:
elixir [45]2 years ago
7 0

The mass of one molecule of sorbitol, C₉H₁₄O₆ is 3.62×10⁻²² g

<h3>Avogadro's hypothesis </h3>

6.02×10²³ molecule = 1 mole of sorbitol, C₉H₁₄O₆

But

1 mole of sorbitol, C₉H₁₄O₆ = (12×9) + (1×14) + (6×16) = 218 g

Thus,

6.02×10²³ molecule = 218 g of C₉H₁₄O₆

With the above idea in mind, we can obtain the mass of one molecule. Details below.

<h3>How to determine the mass of 1 molecule</h3>

The mass of one molecule of C₉H₁₄O₆ can be obtained as illustrated below:

6.02×10²³ molecule = 218 g of C₉H₁₄O₆

Therefore,

1 molecule = 218 / 6.02×10²³

1 molecule = 3.62×10⁻²² g

Thus, the mass of one molecule of C₉H₁₄O₆ is 3.62×10⁻²² g

Learn more about Avogadro's number:

brainly.com/question/26141731

#SPJ1

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Answer:

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3 years ago
What would be the effect on this reaction of increasing the temperature?
Ainat [17]

Answer: D

Explanation: I got it wrong on my test :( and got this answer as correct.

6 0
3 years ago
Read 2 more answers
A cord is used to vertically lower an initially stationary block of mass m kg at a constant downward acceleration of g/4. the bl
Natali5045456 [20]

(a) We know that work is the product of Force and Distance so: (in this case Distance is negative since going down so –d)

work = force * distance

work = M * (g - g/4) * -d

work = -3Mgd/4 <span>

(b) The work by the weight of the block is simply:</span>

work = Mgd <span>

(c) The kinetic energy is simply equivalent to the net work, therefore:</span>

KE = net work

KE = Mgd/4 <span>

(d) The velocity is:</span>

v = √(2*KE/M)

Plugging in the value of KE from c:

v = √(2*Mgd / 4M)

<span>v = √(gd / 2) </span>

5 0
3 years ago
If acid precipitation rain changes the ph of a pond from 7.0 to 5.0, the level of hydrogen ion has changed by a factor of ______
Karolina [17]
When pH=7, [H⁺] =10⁻⁷.
When pH=5, [H⁺]=10⁻⁵.

10⁻⁵/10⁻⁷ =10²=100
The level of hydrogen ions increased by factor 100.
5 0
4 years ago
To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple _______. Then, plot ln(K
Aloiza [94]

Answer:

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us use the thermodynamic definition of the Gibbs free energy and its relationship with Ksp as follows:

\Delta G=-RTln(Ksp)\\\\\Delta G=\Delta H-T\Delta S

Thus, by combining them, we obtain:

-RTln(Ksp)=\Delta H-T\Delta S\\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{T\Delta S}{RT} \\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{\Delta S}{R}

Which is related to the general line equation:

y=mx+b

Whereas:

y=ln(Ksp)\\\\m=-\frac{\Delta H}{R} \\\\x=\frac{1}{T} \\\\b=\frac{\Delta S}{R}

It means that we answer to the blanks as follows:

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.

Regards!

8 0
3 years ago
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