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almond37 [142]
2 years ago
15

Scientists have categorized trees based on whether they keep or lose their leaves each year. Another logical way to categorize t

rees is based on the
A O types of nutrients needed to grow.
amount of oxygen that is released into the air.
B
c. O color of leaves that are produced.
DO type of fruit that is produced.
Chemistry
1 answer:
Zolol [24]2 years ago
5 0

Answer:

D

Explanation:

I think but it is an better attempt than the other guy answer.

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What's the preview of the scientific method
Dafna11 [192]

Explanation:

overall preview would be an expirement is an empirical procedure that arbitrates competing models or hypothesis ☺️

5 0
3 years ago
29.3g CO2 and 20.8g H2O
docker41 [41]

Answer:

the most best answer is 50.1 you never find such type of answer

6 0
2 years ago
Calculate the pH after the addition of 10.0 mL of 0.240 M sodium hydroxide to 50.0 mL of 0.120 M acetic acid.
Goryan [66]

Answer:

pH = 4.58

Explanation:

The reaction of NaOH with acetic acid, CH₃COOH occurs as follows:

NaOH + CH₃COOH → CH₃COO⁻Na⁺ + H₂O

<em>Moles that react:</em>

NaOH = 10mL = 0.010L * (0,240mol / L) = 0.0024 moles NaOH

CH₃COOH = 50.0mL = 0.050L * (0.120mol / L) = 0.0060 moles CH₃COOH

That means after the reaction you will have:

CH₃COOH: 0.0060 mol - 0.0024 mol = 0.0036 moles

CH₃COO⁻Na⁺: 0.0024 moles

in solution, you will have the mixture of a weak acid (Acetic acid), with its conjugate base (sodium acetate, CH₃COO⁻Na⁺). And pH of this buffer can be determined using H-H equation:

pH = pKa + log [A⁻] / [HA]

For Acetic buffer pKa = 4.76:

pH = 4.76 + log [CH₃COO⁻Na⁺] / [CH₃COOH]

<em>Where [] is molarity of each species or moles</em>

<em />

Replacing:

pH = 4.76 + log [0.0024 moles] / [0.0036 moles]

<h3>pH = 4.58</h3>

<em />

6 0
3 years ago
A researcher wants to make a solution of agcl and water at 75 °c. for solid agcl at 75°c, ksp = 1.5 x 10-5.
mars1129 [50]
A.)
dG = -(0.008314)(348K) (1.5 * 10-5)
dG = -(0.008314)(348K (-11.107)
dG = 32 kJ/mol (rounded from 32.14) 
--------
B.)
AgCl(s) >>>> Ag+ and Cl-
<span>Ksp = {Ag+}{Cl-} 
</span><span>1.5 * 10-5 = {Ag+}{Cl-}
</span>1.5 * 10-5 = {X}{X}
<span>X2 = 1.5 x 10-5 
</span>X={Ag+}{Cl-}
Sol / AgCl = 3.873E-3 litres/moles
<span>(3.873E-3 moles AgCl/Litre) (143.32 g AgCl / mol)= 0.56g AgCl</span>
7 0
3 years ago
Which compound releases hydroxide ions in an aqueous solution?
chubhunter [2.5K]
4- KOH

KOH is a strong base. In water it dissociates as 
<span>KOH--> K+ + OH- </span>
<span>A is acetic acid, a weak acid </span>
<span>CH3OH is an alcohol, weakly acidic in water </span>
<span>HCl is a strong acid.</span>
5 0
2 years ago
Read 2 more answers
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