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Rudik [331]
3 years ago
11

Would your results be he same if 1.5 g of barium chloride was used instead of 1.3 g? same with 0.7 g of barium chloride?

Chemistry
1 answer:
pickupchik [31]3 years ago
6 0
For a chemical reaction, the results would be the same with different amounts of barium chloride present if barium chloride is not the limiting reactant of the reaction. The limiting reactant is the substance that is totally consumed when the reaction proceeds to completion. In other words, it dictates the amount of products that will be produced. Otherwise, if barium chloride is the limiting reactant, the amount of barium chloride present would definitely affect the results.  
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The HF bond length is 92 pm, 16% shorter than the sum of the covalent radii of H (37 pm) and F (72 pm). Suggest a reason for thi
Elza [17]

Due to electronegativity difference between H and F atom.

<h3>What is the reason for the difference ?</h3>
  • The bond length of HF is 92 pm. It is 16% shorter than the sum of the covalent radii of H (37 pm) and F (72 pm).
  • The shorter of the bond length is due to the difference in electronegativity between H and F atom. The electronegativity of F is 4.0, whereas the electronegativity of H is 2.1.
  • Greater the difference of electronegativity between the bonded atoms, shorter will be the bond length.
  • As  becomes smaller i.e. as we proceed from HF to HI, this effect becomes lessens and bond length will be more predictable.

Thus from the above conclusion we can say the difference in electronegativity between H and F atom this is the reason for shorter bond length of HF.

Learn more about bond length here :

brainly.com/question/13683866

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3 0
1 year ago
Calculate the molar mass of nitrogen gas if 0.250 g of the gas occupies 46.65 ml at stp
Mashutka [201]
<span>pre-1982 definition STP: 120 g/mol post-1982 definition STP: 122 g/mol The answer to this question depends upon which definition of STP you're using. The definition changed in 1982 from 273.15 K at 1 atmosphere to 273.15 K at 10000 pascals. As a result the molar volume of a gas at STP changed from 22.4 L/mol to 22.7 L/mol. So let's calculate the answer using both definitions and see if your text book is 35 years obsolete. First, determine the number of moles of gas you have. Do this by dividing the volume you have by the molar volume. So pre-1982: 0.04665 / 22.4 = 0.002082589 mol post-1982: 0.04665 / 22.7 = 0.002055066 mol Now divide the mass you have by the number of moles. pre-1982: 0.250 g / 0.002082589 mol = 120.0428725 g/mol post-1982: 0.250 g / 0.002055066 mol = 121.6505895 g/mol Finally, round to 3 significant figures: pre-1982: 120 g/mol post-1982: 122 g/mol These figures are insanely large for nitrogen gas. So let's see if our input data is reasonable. Looking up the density of nitrogen gas at STP, I get a value of 1.251 grams per liter. The value of 0.250 grams in the problem would then imply a volume of about one fifth of a liter, or about 200 mL. That is over 4 times the volume given of 46.65 mL. So the verbiage in the question mentioning "nitrogen gas" is inaccurate at best. I see several possibilities. 1. The word "nitrogen" was pulled out of thin air and should be replaced with "an unknown" 2. The measurements given are incorrect and should be corrected. In any case, if #1 above is the correct reason, then you need to pick the answer based upon which definition of STP your textbook is using.</span>
6 0
3 years ago
Consider the potassium permanganate reaction again.
Rus_ich [418]
Hey there !

Mole ratio :

<span>2 KMnO4 + 16 HCl → 2 KCl + 2 MnCl2 + 8 H2O + 5 Cl2

2 moles KMnO4 ----------------- 8 moles H2O
3.45 moles KMnO4 ------------- (moles H2O )

Moles H2O = 3.45 * 8 / 2

Moles H2O = 27.6 / 2

 = 13.8 moles of H2O

</span>The option that was given is wrong , <span>You're right.</span>
6 0
3 years ago
Read 2 more answers
Balance the following equation and determine the mole ratio of Cl2 to CCl4. CS2 + Cl2 CCl4 + S2Cl2
Andre45 [30]
CS₂ + Cl₂<span> </span>→ CCl₄ + S₂Cl₂<span> [unbalanced equation]

</span>CS₂ + 3Cl₂ → CCl₄ + S₂Cl₂ [balanced equation]

∴ the mole ratio of Cl₂ : CCl₄ is   3  :  1  (option D)
3 0
3 years ago
Read 2 more answers
What is the number of valence electrons in potassium?
Liono4ka [1.6K]
1 or 8 i believe would be the answer
7 0
4 years ago
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