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2 years ago

Would your results be he same if 1.5 g of barium chloride was used instead of 1.3 g? same with 0.7 g of barium chloride?

1 answer:

6 0

For a chemical reaction, the results would be the same with different amounts of barium chloride present if barium chloride is not the limiting reactant of the reaction. The limiting reactant is the substance that is totally consumed when the reaction proceeds to completion. In other words, it dictates the amount of products that will be produced. Otherwise, if barium chloride is the limiting reactant, the amount of barium chloride present would definitely affect the results.

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Can tell the answer pls

Alborosie

Explanation: where the article????

6 0

2 years ago

Phosgene is a potent chemical warfare agent that is now outlawed by international agreement. It decomposes by the reaction: COCl

Oksana_A [137]

Answer:

[CO] = 7.61x10⁻³M

7.61x10⁻³x10³ = 7.61

Explanation:

For a generic equation aA + bB ⇄ cC + dD, the constant of equilibrium (Kc) is:

$Kc = \frac{[C]^cx[D]^d}{[A]^ax[B]^b}$

We need to know the molar concentrations in the equilibrium. In the beginning, there is only COCl₂, and its concentration is the number of moles divided by the volume:

[COCl₂] = 7.73/10.0 = 0.773 M

So, the equilibrium will be:

COCl₂(g) ⇆ CO(g) + Cl₂(g)

0.773 0 0 Initial

-x +x +x Reacts

0.773-x x x Equilibrium

Supposing that x<<0.773, then:

$Kc = \frac{x*x}{0.773}$

7.5x10⁻⁵ = x²/0.773

x² = 5.7975x10⁻⁵

x = √5.7975x10⁻⁵

x = 7.61x10⁻³ M

The supposing is correct, so [CO] = 7.61x10⁻³ x 10³ = 7.61

6 0

2 years ago

How much heat is transferred in the process of completely melting a 1.6kg block of ice starting at -15 degrees Celsius? Is this

mixas84 [53]

Answer:

a) Heat = 590 kJ

b) Endothermic

Explanation:

Endothermic processes absorb energy. The final state contains more energy than the initial state.

Since ice absorbs heat energy in the process of completely melting this is an endothermic process.

The process involves two stages: 1) heating the ice up to the melting point, which is 0ºC, and 2) melting the ice.

1. Heating the ice from -15ºC to 0ºC

a) Formula: Q = m×C×ΔT

m = 1.6 kg

C = 2.108 kJ/kg.ºC (specific heat of ice)

ΔT = 15ºC

b) Calculations:

Q = m×C×ΔT = 1.6 kg × 2.108 kJ/kg.ºC × 15ºC = 50.592 kJ

2. Melting the ice at 0ºC

a) Formula: L = m × ΔHf

m = 1.6 kg

ΔHf = 334 kJ/kg (latent heat of fussion)

b) Calculations

L = m × ΔHf = 1.6 kg × 334 kJ/kg = 534.40 kJ

2. Total heat

50.592 kJ + 534.40 kJ = 584.992 kJ ≈ 590 kJ (rounded to 2 significant figures)

4 0

3 years ago

Fill in the coefficients that will balance the following reaction:

vfiekz [6]

6NaC₂H₃O₂ + Fe₂O₃ → 2Fe(C₂H₃O₂)₃ + 3Na₂O

Explanation:

Given equation;

NaC₂H₃O₂ + Fe₂O₃ → Fe(C₂H₃O₂)₃ + Na₂O

To find the coefficient that will balance this we equation, let us set up simple mathematical algebraic expressions that we can readily solve.

Let us have at the back of our mind that, in every chemical reaction, the number of atom is usually conserved.

aNaC₂H₃O₂ + bFe₂O₃ → cFe(C₂H₃O₂)₃ + dNa₂O

a, b, c and d are the coefficients that will balance the equation.

conserving Na; a = 2d

C: 2a = 6c

H: 3a = 9c

O; 2a + 3b = 6c + d

Fe: 2b = c

let a = 1

solving:

2a = 6c

2(1) = 6c

c = $\frac{2}{6} = \frac{1}{3}$

2b = c

b = $\frac{1}{2} x \frac{1}{3}$ = $\frac{1}{6}$

d = 2a + 3b - 6c = 2(1 ) + (3 x $\frac{1}{6}$ ) - (6 x $\frac{1}{3}$ ) = $\frac{1}{2}$

Now multiply through by 6

a = 6, b = 1, c = 2 and d = 3

6NaC₂H₃O₂ + Fe₂O₃ → 2Fe(C₂H₃O₂)₃ + 3Na₂O

learn more:

Balanced equation brainly.com/question/9325293

#learnwithBrainly

6 0

2 years ago

Calculate AH°rxn from AH°7 values (use table in textbook appendix) a) Cl2 (g) + 2 Na (s) -› 2 NaCl (s) EITHER -411.1kJ/mol b) 2

MrMuchimi

To find AH°rxn, we use the following equation:

What we're going to do is to sum the enthalpy of the products and then substract with the enthalpy of the reactives:

As you can see, we need to multiply by the coefficients of the reaction.

Now, just replace the values of the table:

So the answer is -822.2kJ/mol.

For b:

Now, just replace the values of the table:

The answer for b is -1036kJ/mol.

4 0

9 months ago