Algae is not an abiotic factor.
Answer:
Cr₂S₃
Explanation:
From the question given above, the following data were obtained:
Mass of chromium (Cr) = 0.67 g
Mass of chromium sulfide = 1.2888 g
Empirical formula =?
Next, we shall determine the mass of sulphur (S) in the compound. This can be obtained as follow:
Mass of chromium (Cr) = 0.67 g
Mass of chromium sulfide = 1.2888 g
Mass of sulphur (S) =?
Mass of S = (Mass of chromium sulfide) – (Mass of Cr)
Mass of S = 1.2888 – 0.67
Mass of S = 0.6188 g
Finally, we shall determine the empirical formula of the compound. This can be obtained as follow:
Mass of Cr = 0.67 g
Mass of S = 0.6188 g
Divide by their molar mass
Cr = 0.67 / 52 = 0.013
S = 0.6188 / 32 = 0.019
Divide by the smallest
Cr = 0.013 / 0.013 = 1
S = 0.019 / 0.013 = 1.46
Multiply by 2 to express in whole number
Cr = 1 × 2 = 2
S = 1.46 × 2 = 3
Therefore, the empirical formula of the compound is Cr₂S₃
N<span>etwork of bonded ions is established</span> between two atoms due to transfer of electrons from one atom to the other.
therefore,
Sodium chloride is formed from a network of bonded ions.
hence the right answer is <span>D) salt, NaCl</span>
Answer:
V₂ = 0.98 L
Explanation:
Given data:
Initial volume = 750 mL =0.75 L
Initial pressure = 745 mmHg (745/760 =0.98 atm)
Initial temperature = 25 °C (25 +273 = 298 K)
Final temperature = -35°C (-35+273 = 238 K)
Final volume = ?
Final pressure = 0.60 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
P₁V₁/T₁ = P₂V₂/T₂
V₂ = P₁V₁T₂/T₁ P₂
V₂ = 0.98 atm × 0.75 L × 238 K / 298 K × 0.60 atm
V₂ = 174.93 atm .L. K / 178.8 K.atm
V₂ = 0.98 L
