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Yanka [14]
2 years ago
5

How was mount Everest made? Please i am handing out 100 points

Physics
1 answer:
Simora [160]2 years ago
7 0

Answer:

Mount Everest formed from a tectonic smashup between the Indian and Eurasian tectonic plates tens of millions of years ago.

Explanation:

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Convection is a mode of heat transfer for which types of objects? A. solids and liquids B. gases and solids C. gases only D. liq
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The correct answer to the question will be D). Liquids and gases.

EXPLANATION:

Convection is the type of mode of heat transfer in which there will be actual motion of particles from one part to the another part of a fluid.

In case of liquids, the particles which are present at the bottom of the container get heated up first and become lighter. The lighter particles will go up and the top heavier particles will move downward. Again the same process will be repeated. In this way, a convection cycle is produced.

For instance, heating of water.

In case of gases, same thing happens just like liquid. The air particles will be heated up first and becomes lighter. These heated particles will move upward. Due to this, an empty space will be created in that region. In order to occupy the empty space, the air will flow from another region which is at low temperature as compared to the heated region. Again, the same process will be repeated which will results into the formation of convection cycle .

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. (a) How high a hill can a car coast up (engine disengaged) if work done by friction is negligible and its initial speed is 110
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Answer:

(a) the high of a hill that car can coast up (engine disengaged) if work done by friction is negligible and its initial speed is 110 km/h is 47.6 m

(b) thermal energy was generated by friction is 1.88 x 10^{5} J

(C) the average force of friction if the hill has a slope 2.5º above the horizontal is 373 N

Explanation:

given information:

m = 750 kg

initial velocity, v_{0} = 110 km/h = 110 x 1000/3600 = 30.6 m/s\frac{30.6^{2} }{2x9.8}

initial height, h_{0} = 22 m

slope, θ = 2.5°

(a) How high a hill can a car coast up (engine disengaged) if work done by friction is negligible and its initial speed is 110 km/h?

according to conservation-energy

EP = EK

mgh = \frac{1}{2} mv_{0} ^{2}

gh = \frac{1}{2} v_{0} ^{2}

h = \frac{v_{0} ^{2} }{2g}

  = 47.6 m

(b) If, in actuality, a 750-kg car with an initial speed of 110 km/h is observed to coast up a hill to a height 22.0 m above its starting point, how much thermal energy was generated by friction?

thermal energy = mgΔh

                         = mg (h - h_{0})

                         = 750 x 9.8 x (47.6 - 22)

                         = 188160 Joule

                         = 1.88 x 10^{5} J

(c) What is the average force of friction if the hill has a slope 2.5º above the horizontal?

f d  = mgΔh

f = mgΔh / d,

where h = d sin θ, d = h/sinθ

therefore

f = (mgΔh) / (h/sinθ)

 = 1.88 x 10^{5}/(22/sin 2.5°)

 = 373 N

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