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tino4ka555 [31]
3 years ago
12

Which types of changes must follow the law of conservation of mass?

Physics
2 answers:
Naddika [18.5K]3 years ago
5 0

Answer:

Both physical and chemical changes

PSYCHO15rus [73]3 years ago
3 0

Answer:

Both physical and chemical changes follow the law since when the system is closed to all transfers of matter and energy, the mass of the system must remain constant over time, irrespective of the state.

Explanation:

pls mark brainliest

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 <span>(a) 

Taking the angle of the pitch, 37.5°, and the particle's initial velocity, 18.0 ms^-1, we get: 

18.0*cos37.5 = v_x = 14.28 ms^-1, the projectile's horizontal component. 

(b) 
To much the same end do we derive the vertical component: 

18.0*sin37.5 = v_y = 10.96 ms^-1 

Which we then divide by acceleration, a_y, to derive the time till maximal displacement, 

10.96/9.8 = 1.12 s 

Finally, doubling this value should yield the particle's total time with r_y > 0 

<span>2.24 s

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Why apple fall neuton head now gravity scary :(. gib me good answer im sad D:
arlik [135]

thats how it works and thanks for points

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. Write the following in the scientific notation of 0.0000002400m ​
aleksandr82 [10.1K]

Explanation:

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7 0
2 years ago
a spaceship is traveling at a speed of 15000 km/s from planet b toward planet a the spaceship sends out a signal with a waveleng
Bumek [7]

Answer: 4nmeter

Explanation: The two observer a and b will measure the same wavelength since the speed of the space craft is very small compared with the speed of light c. That is

V which is the speed of space craft 15000km/s = 15000000m/s

Comparing this with the speed of light c 3*EXP(8)m/s we have

15000000/300000000

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Therefore the speed of the space craft V in terms of the speed of light c is 0.1c special relativity does not apply to object moving at such speed. So the wavelength would not be contracted it will remain same for both observers.

4 0
3 years ago
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Alex787 [66]

Explanation:

The given data is as follows.

       Length (l) = 2.4 m

       Frequency (f) = 567 Hz

Formula to calculate the speed of a transverse wave is as follows.

                  f = \frac{5}{2l} \times v

Putting the gicven values into the above formula as follows.

                  f = \frac{5}{2l} \times v

                 567 Hz = \frac{5}{2 \times 2.4 m} \times v

                      v = 544.32 m/s

Thus, we can conclude that the speed (in m/s) of a transverse wave on this string is 544.32 m/s.

5 0
3 years ago
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