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nikklg [1K]
2 years ago
13

The force that accelerates a rocket in outer space is exerted on the rocket by the?

Physics
1 answer:
Nana76 [90]2 years ago
3 0

Gases at pressure are released by rockets as they travel towards space. According to Newton's third law, the combustion chamber's exhaust gases push the rocket with an accelerating force known as the thrust.

<h3>Explain exactly Newton's Third Law:</h3>

According to Newton's third law, if an object A pulls on an object B, then object B must exert an equal-sized and opposite-direction force on the first thing directed in the opposite direction. This law illustrates a symmetry in nature whereby forces always occur in pairs and whereby no body can exert a force without also being subjected to one.

<h3>What are Newton's 3rd law examples?</h3>

Action and response are always equal but always move in the opposite direction, according to Newton's third law of motion. A human walking on the ground, a hammer driving a nail, a magnet attracting a paper clip, and a horse pulling a cart are all examples of Newton's third rule of motion.

To know more about Newton Third Law visit:

brainly.com/question/23772134

#SPJ4

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3 years ago
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What is longitudinal wave?​
nignag [31]

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7 0
3 years ago
At an amusement park, the wheelie carries passengers in a circular path of radius r = 11.2 m. If the angular speed of the wheeli
Dafna1 [17]

Answer:

(a) Tangential velocity will be 38.648 m/sec

(b) Acceleration will be 133.617m/sec^2

Explanation:

We have given radius r = 11.2 m

Angular speed \omega =0.550rev/sec=0.550\times 2\pi =3.454rad/sec

(a) We have to find the tangential velocity

We know that tangential velocity is given by  

v_t=\omega r=3.454\times 11.2=38.684m/sec

(b) We know that acceleration is given by

a=\frac{v^2}{r}=\frac{38.684^2}{11.2}=133.617m/sec^2

8 0
3 years ago
Which action best demonstrates the transformation of mechanical energy to heat energy and light energy?
Vinvika [58]

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5 0
3 years ago
Read the scenario.
tankabanditka [31]

Answer:

distance = 6 m

Explanation:

- Distance is a scalar quantity (so, only magnitude, no direction), and it is calculated as the scalar sum of all the distances travelled by an object during its motion, regardless of the direction. So, in this problem, the distance covered by the pinecone is

d = 4 m + 2 m = 6 m

- Displacement is a vector quantity (magnitude+direction), and its magnitude is calculate as the distance in a straight line between the final position and the initial position of the object. In this case, the final position is 2 m west and the initial position is 0 m, so the displacement of the pinecone is

d = 2 m west - 0 m = 2 m west

So, a scalar quantity from this scenario is

distance = 6 m

4 0
3 years ago
Read 2 more answers
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