HELP

If the magnetic force is 3.5 × 10–2 N, how fast is the charge moving?

Sveta_85 [38]

Answer:

The velocity of charge is 1.1×10⁴

Option(D)

Explanation:

F = q(v×B)

3.5×10-²= (8.4×10-⁴)*(v)*(6.7×10-³)*sin35

v = (3.5)/(8.4×6.7×0.57) × 10⁵

v = 3.5/32.08 × 10⁵

v = 0.109 × 10⁵

v ≈ 1.1 × 10⁴ m/s

6 0

3 years ago

Read 2 more answers

A student at a window on the second floor of a dorm sees her physics professor walking on the sidewalk beside the building. she

klasskru [66]

Refer to the diagram shown below.

In order for the balloon to strike the professor's head, th balloon should drop by 18 - 1.7 = 16.3 m in the time at the professor takes to walk 1 m.
The time for the professor to walk 1 m is
t = (1 m)/(0.45 m/s) = 2.2222 s

The initial vertical velocity of the balloon is zero.
The vertical drop of the balloon in 2.2222 s is
h = (1/2)*(9.8 m/s²)*(2.2222 s)² = 24.197 m

Because 24.97 > 16.3, the balloon lands in front of the professor, and does not hit the professor.

The time for the balloon to hit the ground is
(1/2)*(9.8)*t² = 18
t = 1.9166 s

The time difference is 2.2222 - 1.9166 = 0.3056 s
Within this time interval, the professor travels 0.45*0.3056 = 0.175 m
Therefore the balloon falls 0.175 m in front of the professor.

Answer:
The balloon misses the professor, and falls 0.175 m in front of the professor.

8 0

3 years ago

The last main subatomic particle to be discovered was the _____.

kati45 [8]

<span>The last main subatomic particle to be discovered was the antihelium-4. It was discovered on 2011 and it is measured and produces through the STAR detector. The Antihelium-4 was discovered accidentally when an experiment was conducted. It is also the first particle that was discovered by the means of experiment.</span>

7 0

3 years ago

A spring with spring constant 15.5 N/m hangs from the ceiling. A ball is suspended from the spring and allowed to come to rest.

Aloiza [94]

Answer:

A) 138.8g

B)73.97 cm/s

Explanation:

K = 15.5 Kn/m

A = 7 cm

N = 37 oscillations

tn = 20 seconds

A) In harmonic motion, we know that;

ω² = k/m and m = k/ω²

Also, angular frequency (ω) = 2π/T

Now, T is the time it takes to complete one oscillation.

So from the question, we can calculate T as;

T = 22/37.

Thus ;

ω = 2π/(22/37) = 10.5672

So,mass of ball (m) = k/ω² = 15.5/10.5672² = 0.1388kg or 138.8g

B) In simple harmonic motion, velocity is given as;

v(t) = vmax Sin (ωt + Φ)

It is from the derivative of;

v(t) = -Aω Sin (ωt + Φ)

So comparing the two equations of v(t), we can see that ;

vmax = Aω

Vmax = 7 x 10.5672 = 73.97 cm/s

6 0

3 years ago

A person hears sound wave beast at 3000Hz at the temperature of 30 °C. What is the person's ear canal length? Please explain

Evgen [1.6K]

Answer:

The person's ear canal length is 2.91 cm.

Explanation:

Given that,

Frequency = 3000 Hz

Temperature = 30°C

We need to calculate the speed

Using equation of sound wave with temperature

[texs]v(t)=331+0.6\times T[/tex]

Put the value of T

$v(t)=331+0.6\times30^{\circ}\ C$

$v(t)=349\ m/s$

We need to calculate the length

Using formula of closed organ pipe

$f=\dfrac{v}{4L}$

$L=\dfrac{v}{4f}$

Where, L = length

v = velocity

f = frequency

Put the value into the formula

$L=\dfrac{349}{4\times3000}$

$L=0.0291\ m$

$L=2.91\times10^{-2}\ m$

$L=2.91\ cm$

Hence, The person's ear canal length is 2.91 cm.

4 0

3 years ago