Answer:
A) To true. he pressure at the bottom of the pool decreases by exactly the same amount as the atmospheric pressure decreases
Explanation:
Let us propose the solution of this problem before seeing the final statements. The pressure increases with the depth of raposin due to the weight of water that is above the person and also the pressure exerted by the atmosphere on the entire pool, the equation describing this process is
P =
+ ρ g y
Where
is the atmospheric pressure, ρ the water density, and 'y' the depth measured from the surface.
Let's examine this equation in we see that the total pressure is directly proportional to the atmospheric pressure and depth
Now we can examine the claims
A) To true. State agreement or with the equation above
B) False. Pressure changes with atmospheric pressure
C) False. It's the opposite
D) False. They are directly proportional
Answer:
31.28m/s
Explanation:
We can use the third key equation of accelerated motion
Δd = viΔt+1/2aΔt^2
subtitute in the values we know
41.6 = vi(1.89)+1/2(-9.8)(1.89)^2
41.6 = vi(1.89) - 17.52
59.12 = vi(1.89)
vi = 31.28
In a quarter of an hour it will travel 1/4 x 90 = 22.5Km
Answer:
b) bend away from the normal
Explanation:
According to snell's law , if i be the angle of incidence and r be the angle of refraction
sin i / sin r = 1.33 / 2.42
sin i / sin r = .55
Hence sin r > sin i
r > i
In other words angle of refraction will be more than angle of incidence . So, the ray will bend away from the normal .