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sweet-ann [11.9K]
2 years ago
13

Andy pushes a box to the right with 5 N of force. Kristen pushes the box to the left with 3 N of force. What will be the resulti

ng (net) force's magnitude and direction?
Physics
1 answer:
REY [17]2 years ago
6 0
The forces are applied in opposite direction.
So the net force will be the difference of both forces.
net force =5-3=2N

This force will be in direction of 5N(bigger force) means in direction which Andy is pushing.
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6. A 50 N block is raised 2 m. If the net work done on the block is 50 J, what is the applied force on the block?
geniusboy [140]

Answer:

F = 75[J]

Explanation:

We know that work is defined as the product of force by distance.

In this way we have two forces, the weight of the block down, and the force that bring about the block to rise.

W = -(F_{weight*d})+(F_{upward}*d)

where:

W = work = 50 [J]

d = distance = 2 [m]

Fweight = 50 [N]

Fupward [N]

Now replacing:

50=-(50*2)+(F_{upward}*2)\\50+100=F_{upward}*2\\F_{upward}=150/2\\F_{upward}=75[J]

5 0
2 years ago
Which chemical equation is balanced?
nika2105 [10]

Answer:

<h3>C no.</h3>

Explanation:

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6 0
2 years ago
Read 2 more answers
A 6.5-l sample of nitrogen at 25°c and 1.5 atm is allowed to expand to 13.0 l. the temperature remains constant. what is the fin
Katarina [22]
The formula that we will going to use in this question is simply P1V1/T1 = P2V2/T2 where T is the constant.
P1V1 = P2V2 
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The answer in this question is 1.5 atm
5 0
2 years ago
True or false as heat and pressure decreases one type of metamorphic rock will transform into another type
dezoksy [38]

Answer: True

Explanation:  Metamorphism is the changing of rocks by heat and pressure. During this process, rocks change either physically and/or chemically. They change so much that they become an entirely new rock. Figure 4.22: The platy layers in this large outcrop of metamorphic rock show the effects of pressure on rocks during metamorphism.

6 0
2 years ago
Can someone help me on how to do this?
Galina-37 [17]

Explanation:

Recall that

1\:\text{micron} = 1\:\mu\text{m} = 10^{-6}\:\text{m} so the speed of the bacterium is

v = \dfrac{6.82×10^{-6}\:\text{m}}{3.5\:\text{s}} = 1.9×10^{-6}\:\text{m/s}

Next, we convert this speed to km/hr. Recall that

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Therefore,

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= 6.8×10^{-6}\:\text{km/hr}

8 0
2 years ago
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