As we know that electric field at any point caused due to a point charge given by, kQ/r^2
Where, k is dielectric constant of medium, Q is the point charge and r is the distance between the point charge and point where electric field is to be measured.
Let us assume a charge of q is placed at x=+20cm to make electric field at
x=+10cm zero.
Total electric field at x=+10cm can be shown by equation,
(k X 2.20 X 10^-12)/(10-0)^2 + (k X -4.80 X 10^-12)/(10-(-11))^2 + (k X
q)/(10-20)^2 = 0
=> 2.20 X 10^-14 - 1.09 X 10^-14 + q X 10^-2 = 0
=> q = 1.09 X 10^-12 - 2.20 X 10^-12
=> q = -1.1 X 10^-12 Coulombs or -1.1 pC
Answer:
A: In an observer's reference frame, motion lacking uniform velocity includes motion at constant or variable speed in a circle; and motion of a reciprocating device. Supposing the zero refers to the “uniform velocity” rather than the motion removes the possibility of an object at rest.
Explanation:
Answer: Planning
Explanation: cause i got it right
Answer:
A straight line on a graph indicates that there is a direct or linear relationship between the dependent variable and independent variable.
Explanation:
<em>It's more linear then direct but put both if you want!</em>
Answer:
a. 0.8 mW/m² b. 1.6 mW/m² c. 6.4 mW/m²
Explanation:
Intensity,I = P/A were P = power and A = area = 4πr² were r = distance from electric guitar = 5.0 m.
a. When P = 0.25 W, I = 0.25 W/4π5² = 0.25 W/100π = 0.00079 W/m² ≅ 0.0008 W/m² = 0.8 mW/m²
b. When P = 0.50 W, I = 0.50 W/4π5² = 0.50 W/100π = 0.00156 W/m² ≅ 0.0016 W/m² = 1.6 mW/m²
c. When P = 2.0 W, I = 2.0 W/4π5² = 2.0 W/100π = 0.00636 W/m² ≅ 0.0064 W/m² = 6.4 mW/m²