Question

Review. A light spring of force constant 3.85 N/m is compressed by 8.00 cm and held between a 0.250-kg block on the left and a 0.500-kg block on the right. Both blocks are at rest on a horizontal surface. The blocks are released simultaneously so that the spring tends to push them apart. Find the maximum velocity each block attains if the coefficient of kinetic friction between each block and the surface is(a) 0,

Answer 1

The spring exerts on each block an outward force of magnitude

$\left|\mathrm{F}_{\mathrm{s}}\right|=\mathrm{kx}=(3.85 \mathrm{~N} / \mathrm{m})(0.08 \mathrm{~m})=0.308 \mathrm{~N}$

$Take the +\mathrm{x} direction to the right. For the light block on the left, the vertical forces are given by$

$\mathrm{F}_{\mathrm{g}}=\mathrm{mg}=(0.250 \mathrm{~kg})\left(9.80 \mathrm{~m} / \mathrm{s}^2\right)=2.45 \mathrm{~N} \\and \ \sum \mathrm{F}_{\mathrm{y}}=0 so \mathrm{n}-2.45 \mathrm{~N}=0 \rightarrow \mathrm{n}=2.45 \mathrm{~N} \\Similarly, for the heavier block,$

$\mathrm{n}=\mathrm{F}_{\mathrm{g}}=(0.500 \mathrm{~kg})\left(9.80 \mathrm{~m} / \mathrm{s}^2\right)=4.90 \mathrm{~N}$

$\begin{aligned}&\sum F_x=m a_x:-0.308 \mathrm{~N}=(0.250 \mathrm{~kg}) \mathrm{a} \\&\mathrm{a}=-1.23 \mathrm{~m} / \mathrm{s}^2\end{aligned} \\\\ For the heavier block, \\ +0.308 \mathrm{~N}=(0.500 \mathrm{~kg}) \mathrm{a} \mathrm{a}=0.616 \mathrm{~m} / \mathrm{s}^2$

What is kinetic energy?

The kinetic energy  is the energy that it possesses due to its motion.

To accelerate an object, we need to apply force. To apply force, we have to be compelled to do work. When work is done on an object, energy is exchanged, and the object moves with a unused steady speed. We call the energy that's exchanged kinetic energy, and it depends on the mass and speed accomplished.

Kinetic energy is a scalar quantity, it is entirely described by magnitude

To learn more about kinetic energy , visit:

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