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choli [55]
1 year ago
12

Describe the difference between the three states of matter in terms of movement behavior at room temperature and how they intera

ct with accounting?
Physics
1 answer:
yuradex [85]1 year ago
5 0

In solids, the atoms are closely bound to each other. The only movement possible for the atoms in this state of matter is vibration. Solids have a fixed shape. Therefore when they are put in a container, the solids remain in their initial shape.

In liquids, the atoms are loosely bound compared to atoms in solid. And the atoms are free to vibrate and to slide past each other. The liquids have fixed volume but have no fixed shape. Therefore, when they are poured into a container, their volume will be the same, but the liquid will take the shape of the container.

In gas, the atoms are very loosely bound. and the atoms are very free to vibrate and move through space. Gases do not have either fixed volume or a fixed shape. Therefore, when they are poured into a container they take the volume and the shape of the container.

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Volunteerism involves giving __________ to others without receiving payment.
soldier1979 [14.2K]

Answer:

Time and services

I'm sorry If I'm wrong

4 0
3 years ago
If al snow and glaiers melted, would the sea level rise or fall
Kobotan [32]
The sea level would rise because the snow and glaciers are water 

4 0
3 years ago
A 12.0-g bullet is fired horizontally into a 109-g wooden block that is initially at rest on a frictionless horizontal surface a
kykrilka [37]

Answer:

v₀ = 280.6 m / s

Explanation:

we have the shock between the bullet and the block that we can work with at the moment and another part where the assembly (bullet + block) compresses a spring, which we can work with mechanical energy,

We write the mechanical energy when the shock has passed the bodies

   Em₀ = K = ½ (m + M) v²

We write the mechanical energy when the spring is in maximum compression

Em_{f} = K_{e} \\= \frac{1}{2} kx^2\\    Em_0 = Em_{f}

½ (m + M) v² = ½ k x²

Let's calculate the system speed

   v = √ [k x² / (m + M)]

   v = √[152 ×0.78² / (0.012 +0.109) ]

   v = 27.65 m / s

This is the speed of the bullet + Block system

Now let's use the moment to solve the shock

Before the crash

   p₀ = m v₀

After the crash

p_{f} = (m + M) v

The system is formed by the bullet and block assembly, so the forces during the crash are internal and the moment is preserved

 p_0 =  p_{f}

  m v₀ = (m + M) v

  v₀ = v (m + M) / m

let's calculate

v₀ = 27.83 (0.012 +0.109) /0.012

  v₀ = 280.6 m / s

4 0
2 years ago
Suppose the ring rotates once every 4.30 ss . If a rider's mass is 58.0 kgkg , with how much force does the ring push on her at
Stells [14]

Answer:

422.36 N

Explanation:

given,

time of rotation = 4.30 s

T = 4.30 s

Assuming the diameter of the ring equal to 16 m

radius, R = 8 m

v = \dfrac{2\pi R}{T}

v = \dfrac{2\pi\times 8}{4.30}

  v = 11.69 m/s

now, Force does the ring push on her at the top

- N - m g = \dfrac{-mv^2}{R}

N + m g = \dfrac{mv^2}{R}

N = \dfrac{mv^2}{R}- m g

N = m(\dfrac{v^2}{R}- g)

N = 58\times (\dfrac{11.69^2}{8}- 9.8)

N = 422.36 N

The force exerted by the ring to push her is equal to 422.36 N.

6 0
2 years ago
Someone pls help with only if you know correct answer!???
Roman55 [17]

Answer:

A 2.0 kg ball, A, is moving with a velocity of 5.00 m/s due west. It collides with a stationary ball, B, also with a mass of 2.0 kg. After the collision

Explanation:

5 0
2 years ago
Read 2 more answers
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