To solve this problem it is necessary to apply the concepts given in the kinematic equations of movement description.
From the perspective of angular movement, we find the relationship with the tangential movement of velocity through

Where,
Angular velocity
v = Lineal Velocity
R = Radius
At the same time we know that the acceleration is given as the change of speed in a fraction of the time, that is

Where
Angular acceleration
Angular velocity
t = Time
Our values are




Replacing at the previous equation we have that the angular velocity is



Therefore the angular speed of a point on the outer edge of the tires is 66.67rad/s
At the same time the angular acceleration would be



Therefore the angular acceleration of a point on the outer edge of the tires is 
Hello!
A graph that shows how position is depending on time is known as a Position Time Graph.
This is a graph used in Physics to help us understand how motion (positive/negative velocity) changes over a period of time. Motion can be seen in two ways on this graph: constant velocity and changing velocity, otherwise known as acceleration.
Hopes this help you answer your question!
4 is the difference sorry if i got it wrong :( :(
Alright here the answer to number 2