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andreev551 [17]
3 years ago
11

A jet airliner moving initially at 693 mph (with respect to the ground) to the east moves into a region where the wind is blowin

g at 798 mph in a direction 37◦ north of east. What is the new speed of the aircraft with respect to the ground? Answer in units of mph.
Physics
1 answer:
Nesterboy [21]3 years ago
7 0

Answer:

The new speed of the aircraft with respect to the ground is 1414.3 mph.

Explanation:

Given that,

Angle = 37°

Velocity of jet airliner = 693 mph

Velocity of wind = 798 mph

We know that,

The new velocity of the aircraft with respect to the ground

v=v_{a}+v_{w}

We need to calculate the new speed of the aircraft with respect to the ground

Using formula for velocity

v=\sqrt{(v_{a})^2+(v_{w})^2+2v_{a}v_{w}\cos\theta}

Put the value into the formula

v=\sqrt{(693)^2+(798)^2+2\times693\times798\cos37}

v=1414.3\ mph

Hence, The new speed of the aircraft with respect to the ground is 1414.3 mph.

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To solve the problem it is necessary to take into account the concepts of kinematic equations of motion and the work done by a body.

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