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2 years ago

10

Correct displacement 4km south,2 km north, 5km south, and 5 km north

1 answer:

babymother [125]2 years ago

8 0

Answer:

2 km due south.

Explanation:

We need to find the displacement of 4km south,2 km north, 5km south, and 5 km north.

Let south is negative direction and north is positive direction.

The shortest path covered by an object is called its displacement.

D = -4+2-5+5

D = -2 km

So, the displacement is 2 km and it is in south direction.

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alexdok [17]

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2 years ago

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A solid metal ball of radius 1.5 cm bearing a charge of -15 nC is located near a hollow plastic ball of radius 1.9 cm bearing a

blsea [12.9K]

We have that the electric field at the center of the metal ball due only to the charges on the surface of the metal ball is

$E=7*10^{9}N/C$

From the question we are told that

A solid metal ball of radius 1.5 cm

bearing a charge of -15 nC is located near a hollow plastic ball of radius 1.9 cm bearing

uniformly distributed charge of -7 nC

The distance between the centers of the balls is 9 cm

Generally the equation for the electric field is mathematically given as

$E=\frac{kq_2}{d^2}\\\\E=\frac{(9*10^9)7*10^{-2}}{9*10^{-2}}\\\\$

$E=7*10^{9}N/C$

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2 years ago

200 Coulombs of charge passes through a point in a circuit for 0.6 minutes. what is the magnitude of the current flowing

Tasya [4]

Answer:

5.56 A

Explanation:

From the question,

Q = it.............. Equation 1

Where Q = charges, i = current, t = time.

Make i the subject of the equation

i = Q/t.............. Equation 2

Given: Q = 200 coulombs, t = 0.6 minutes = (0.6×60) seconds

Substitite these values into equation 2

i = 200/(0.6×60)

i = 5.56 A

Hence the magnitude of the current flowing through the circuit is 5.56 A

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2 years ago

john is using a pulley to lift the sail on his sailboat. the sail weighs 150N and he must lift it at 4.0m. how much work must be

gogolik [260]

The work done on the sail is 600 J

Explanation:

The work done to lift the sail is equal to the gain in gravitational potential energy of the sail, therefore is:

$W=mg\Delta h$

where

m is the mass of the sail

g is the acceleration of gravity

(mg) is the weight of the sail

$\Delta h$ is the change in height of the sail

In this problem we have

mg = 150 N (weight)

$\Delta h = 4.0 m$

Substituting, we find the work done:

$W=(150)(4.0)=600 J$

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2 years ago

Who has the best answer for this

ioda

Answer:

electricity because it has more percentage nd energy

Explanation:

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1 year ago