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2 years ago

Write a hypothesis about the use of an object's physical

Physics

1 answer:

KengaRu [80]2 years ago

3 0

If the mass of the object and the volume of the object is determined;

Then, the density of the object is determined by taking the ratio of the mass and volume.

<h3>What is density of an object?</h3>

The density of an object is the ratio of the mass and volume of that object.

Mathematically;

Density = mass/volume

To determine the density of an object therefore, the physical characteristics of mass and the volume of the object are measured.

The mass of the object is obtained using a scale or a balance.

The volume of the object if a solid is obtained using a displacement bottle. If it is a liquid, a measuring cylinder is used.

The density of the object is then obtained by taking the ratio of the mass and the volume of the object.

In conclusion, the density of an object is determined from the volume and mass ratio.

Learn more about density at: brainly.com/question/1354972

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If the torque required to loosen the nut that is holding a flat tire in a place on a car has a magnitude of 35 N•m what minimum

VashaNatasha [74]

Answer: F = 130 N

Explanation: Solution:

Convert first 27 cm to m.

27 cm x 0.01 m / 1 cm = 0.27 m

Calculate the torque using T = Fd

Derive to find force F

F = T /d

= 35 N.m / 0.27 m

= 130 N

4 0

3 years ago

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igor_vitrenko [27]

Answer:

A. True.

Explanation:

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3 years ago

Frankie and carol are playing tug a war using a rope . if frankie , on the right , pulls with the force of 7n what force is caro

vampirchik [111]

If the net force is 4 N, and Frankie is pulling the rope with 7 N, Carol must be pulling the rope with 11 N (I think that Carol is going to win the tug-of-war...).

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3 years ago

5. A 905 kg test car travels around a 3.04 km circular track. If the magnitude of the centripetal force is 2100 N. What is the c

balu736 [363]

Answer:

Explanation:

The equation for centripetal force is

$F=\frac{mv^2}{r}$ . We have all the values we need except for the radius. We have the circumference of the circle, though, so we will solve for the radius using that and the fact that C = 2πr:

3.04 = 2(3.1415)r and

r = .484 m, to the correct number of sig fig's.

Now that we have everything we need and isolating the v NOT squared:

$v=\sqrt{\frac{rF}{m} }$ and filling in:

$v=\sqrt{\frac{(.484)(2100)}{905} }$ . This answer will need 2 sig fig's since 2100 has 2 sig fig's in it. That means that the velocity of the test car is