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matrenka [14]
3 years ago
14

How does inertia affect a person who is not wearing a seatbelt during a collision?

Physics
2 answers:
elena-14-01-66 [18.8K]3 years ago
7 0
I dosen't hurt them or just keep them safe 
son4ous [18]3 years ago
6 0
When the car stops, inertia causes the person to continue forward at the speed of the car prior to stopping
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he graph shows the distance (x) traveled by an aircraft traveling at constant velocity in corresponding time intervals (t). What
Feliz [49]

Answer:

B linear, 825 meters

Explanation:

5 0
3 years ago
Which is an example of a multicellular organism? A. gorilla B. amoeba C. bacterium D. paramecium
IgorLugansk [536]
The answer is A: Gorilla.

In the animal kingdom, all organisms are multicelluar.
4 0
4 years ago
A 0.171-kilogram hockey puck is struck by a hockey stick. If the force from the hockey stick is 30.2 Newtons, but the puck also
Komok [63]

Answer:

a = 156.14 m/s^2

Explanation:

Using the laws of newton:

∑F = ma  

where ∑F is the sumatory of forces, m the mass and a the aceleration.

so:

F -f_k = ma

where F is the force from the hockey stick and f_k is the force of friction.

Replacing values, we get:

(30.2N) - (3.5N)= (0.171kg)a

Finally, solving for a:

a = 156.14 m/s^2

4 0
3 years ago
A projectile is thrown from the top of a building with an initial velocity of 30 m/s in the horizontal direction. If the top of
Svetlanka [38]

Answer:

V = 38.582 m/s

Explanation:

Initial Vertical Velocity = 0

Let's use the motion equation given below to solve for the final vertical velocity:

v^2 - u^2 = 2*a*s

Here a = 9.81 m/s^2

and s = 30 m

Solving for v, we get:

v = 24.261 m/s

This is just the vertical velocity, to get the total velocity we need to add the horizontal component of velocity with this:

Total velocity = Sqrt ( Horizontal Velocity^2 + Vertical Velocity^2)

V = \sqrt{(V_x)^2+(V_y)^2}

where V_x = 30  and V_y = 24.261

V = 38.582 m/s

3 0
3 years ago
An airplane flies with a velocity of 55.0 m/s [35o N of W] with respect to the air (this is known as air speed). If the velocity
andrew-mc [135]
V - the wind velocity;
53° - 35° = 18°
v² = 55² + 40² - 2 · 55 · 40 · cos 18°
v² = 3025 + 1600 - 2 · 55 · 40 · 0.951
v² = 440.6
v = √440.6
v = 20.99 ≈ 21 m/s
Answer: The wind velocity is 21 m/s.  
5 0
3 years ago
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