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Vera_Pavlovna [14]
3 years ago
10

Match the following moves to the correct total distance and displacement of the moves.

Physics
1 answer:
MAVERICK [17]3 years ago
5 0
A. Move 2 m east and then 12 m east; displacement is 14 m east and the distance is 14 m
B. Move 10 m east and then 12 m west, the displacement is 2 m west and the distance is 22 m.
C. Move 8 m west and then 16 m east; the displacement is 8 m east and the distance is 24 m
D. Move 12 m west and then 8 m east; the displacement is 4 m and the distance is 20 m
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A particle whose speed is 50 m/sec moves along the line from A(2,1) to B (9,25)
WINSTONCH [101]

First, calculate for the distance between the given points A and B by using the equation,

<span>                                                D = sqrt ((x2 – x1)2 + (y2 – y1)2)</span>

 

Substitute the known values:

<span>                                                D = sqrt((9 – 2)2 + (25 – 1)2)</span>

<span>                                                D = 25 m</span>

 

I assume the unknown here is the time it would require for the particle to move from point A to B. This can be answered by dividing the calculated distance by the speed given above.

<span>                                                t = (25 m)/ (50 m/s) = 0.5 s</span>

 

<span>Thus, it will take 0.5s for the particle to complete the route. </span>

3 0
3 years ago
A diver comes off a board with arms straight up and legs straight down, giving her a moment of inertia about her rotation axis o
mihalych1998 [28]

Answer:

θ₁ = 0.5 revolution

Explanation:

We will use the conservation of angular momentum as follows:

L_1=L_2\\I_1\omega_1=I_2\omega_2

where,

I₁ = initial moment of inertia = 18 kg.m²

I₂ = Final moment of inertia = 3.6 kg.m²

ω₁ = initial angular velocity = ?

ω₂ = Final Angular velocity = \frac{\theta_2}{t_2} = \frac{2\ rev}{1.2\ s} = 1.67 rev/s

Therefore,

(18\ kg.m^2)\omega_1 = (3.6\ kg.m^2)(1.67\ rev/s)\\\\\omega_1 = \frac{(3.6\ kg.m^2)(1.67\ rev/s)}{(18\ kg.m^2)}\\\\\omega_1 = \frac{\theta_1}{t_1} =  0.333\ rev/s\\\\\theta_1 = (0.333\ rev/s)t_1

where,

θ₁ = revolutions if she had not tucked at all = ?

t₁ = time = 1.5 s

Therefore,

\theta_1 = (0.333\ rev/s)(1.5\ s)\\

<u>θ₁ = 0.5 revolution</u>

4 0
3 years ago
A girl dribbling a basketball is running a court that is 100 m in length. It takes her 4.2 seconds to reach the end of the court
Travka [436]

Divide the distance traveled by the time it took:

(100 m) / (4.2 s) ≈ 23.8 m/s

6 0
3 years ago
Starlight is released during which nuclear reaction?
Likurg_2 [28]

Answer:

D. Nuclear fusion

Explanation:

Nuclear fusion is a nuclear reaction where nuclei of atoms( one of low atomic number and another with a higher atomic number) join together to form a much bigger nucleus and release a lot of energy.In the sun, which is a star of course, where light is released,hydrogen is converted to helium and the process releases massive energy into space in form of heat and light.

6 0
4 years ago
Read 2 more answers
A 1200-kg car accelerates it’s speed from 4 m/s to 10 m/s in 3 seconds. Find the car average speed , the car acceleration , the
dsp73

Answer:

Given: mass 1200kg

initial velocity: 4m/s

finial velocity: 10 m/s

time 3 sec

then

speed; initial velocity + final velocity/2

4+10/3

: 4.66m/s2

8 0
3 years ago
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