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mart [117]
2 years ago
9

A particle of mass 16kg travelling with a velocity of 10m/s is acted upon by a steady force of friction in a direction opposite

that of its motion. Find the speed of the particle after 10 seconds if the force of friction is 25N.​
Physics
1 answer:
Rudiy272 years ago
5 0

The speed of the particle after 10 seconds is, 25.88m/s.

To find the answer, we have to know more about the equations of motion.

<h3>How to find the speed of the particle after 10s?</h3>
  • It is given that,

                          m=16kg\\u=10m/s\\t=10s\\f=25N

  • It is clear from the question that, the motion is balanced by the frictional force. Thus, the acceleration will be,

                        ma=f\\a=\frac{f}{m} =\frac{25}{16}=1.6m/s^2

  • We have the equation of motion for the distance travelled as,

           S=ut+\frac{1}{2}at^2=(10*10)+(\frac{1.6*10^2}{2})=178.13m

  • Thus, by another equation of motion connecting a, S, and u, we get the final speed after 10s as,

                v=\sqrt{u^2+2aS} =\sqrt{10^2+(2*1.6*178.13)} =25.88m/s

Thus, we can conclude that, the speed of the particle after 10 seconds is, 25.88m/s.

Learn more about the equations of motion here:

brainly.com/question/24595388

#SPJ1

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In the absence of air resistance two balls are thrown upward from the same launch point. Ball a rises to a maximum height above
diamong [38]

Answer:

Va is two times greater than Vb

Explanation:

The maximum height reached by the balls are:

Ymax = \frac{Vo^2}{2g}

Since we are told that Ya = 4Yb:

Ya =  \frac{Va^2}{2g} = 4* Yb = 4 * \frac{Vb^2}{2g}

Simplifying the equation:

Va^2 = 4*Vb^2

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5 0
3 years ago
Models that explain the formation of the solar system through a series of gradual steps are considered evolutionary theories. Wh
lora16 [44]

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Catastrophic theories

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Therefore the answer is -

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4 0
3 years ago
Be sure to answer all parts. Without stratospheric ozone (O3), harmful solar radiation would cause gene alterations. Ozone forms
Ratling [72]

Answer:

for C-Cl  bond \lambda_1=3.66\times 10^{-9}\ m

for O-O bond \lambda_2=2.43\times 10^{-9}\ m

Explanation:

  • We have the bond enegy for C-Cl, BE_1=327\ kJ.mol^{-1}= 327000\times 1.66\times 10^{-22}\ J\ per\ molecule
  • bond enegy for C-Cl, BE_2=494\ kJ.mol^{-1}= 494000\times 1.66\times 10^{-22}\ J\ per\ molecule

<u>Now as we know the energy of electromagnetic waves is given by:</u>

E=h.\nu

here E = BE

<u>Then for C-Cl:</u>

327000\times 1.66\times 10^{-22}=6.63\times 10^{-34}\times \nu_1

\nu_1=8.18733\times 10^{16}\ Hz

Now wavelength:

\lambda_1=\frac{c}{\nu_1}

\lambda_1=\frac{3\times 10^8}{8.18733\times 10^{16}}

\lambda_1=3.66\times 10^{-9}\ m

<u>For O2:</u>

494000\times 1.66\times 10^{-22}=6.63\times 10^{-34}\times \nu_2

\nu_2=1.236863\times 10^{17}\ Hz

Now wavelength:

\lambda_2=\frac{c}{\nu_2}

\lambda_2=\frac{3\times 10^8}{1.236863\times 10^{17}}

\lambda_2=2.43\times 10^{-9}\ m

8 0
3 years ago
20 PTS!
klemol [59]
  • its acceleration is zeo

If an object is moving with a constant velocity, then by definition it has zero acceleration. So there is no net force acting on the object. The total work done on the object is thus 0 (that's not to say that there isn't work done by individual forces on the object, but the sum is 0 ).

8 0
3 years ago
Read 2 more answers
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