Question

A particle of mass 16kg travelling with a velocity of 10m/s is acted upon by a steady force of friction in a direction opposite that of its motion. Find the speed of the particle after 10 seconds if the force of friction is 25N.​

Answer 1

The speed of the particle after 10 seconds is, 25.88m/s.

To find the answer, we have to know more about the equations of motion.

How to find the speed of the particle after 10s?

• It is given that,

                          $m=16kg\\u=10m/s\\t=10s\\f=25N$

• It is clear from the question that, the motion is balanced by the frictional force. Thus, the acceleration will be,

                        $ma=f\\a=\frac{f}{m} =\frac{25}{16}=1.6m/s^2$

• We have the equation of motion for the distance travelled as,

           $S=ut+\frac{1}{2}at^2=(10*10)+(\frac{1.6*10^2}{2})=178.13m$

• Thus, by another equation of motion connecting a, S, and u, we get the final speed after 10s as,

                $v=\sqrt{u^2+2aS} =\sqrt{10^2+(2*1.6*178.13)} =25.88m/s$

Thus, we can conclude that, the speed of the particle after 10 seconds is, 25.88m/s.

Learn more about the equations of motion here:

brainly.com/question/24595388

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