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4 years ago

6

In the combination of resistors above, consider the 1.50 µΩ and 0.75 µΩ. How can you classify the connection between these two r

esistors?

1 answer:

Airida [17]4 years ago

3 0

Answer: they are connected in series.

Explanation:

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What is pneumatic troubleshooting

jekas [21]

Answer:

Compressed Air.

Explanation:This stuffs at plantengineering.com my fellow student. Good luck on the test!

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3 years ago

The input power for a thermostat is wired to the

masya89 [10]

Answer:

A. R

Explanation:

There are basically two wires that supply input power to the thermostat namely the C wire which is the common wire and the R wire .The G wire simply completes the input power circuit from the R-leg of the power supply.On the another hand the Y wire also completes the circuit from the compressor fan contactor to the R-leg of the power supply . While the W wire completes the path to the heater contactor coil.

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4 years ago

Find the capacitance reactance of a 0.1 micro frequency capacitor 50Hz and at 200Hz

Paraphin [41]

Complete Question:

Find the capacitive reactance of a 0.1 microfarad capacitor with frequency 50Hz and at 200Hz.

Answer:

I. Capacitive reactance = 31826.86 Ohms.

II. Capacitive reactance = 7956.72 Ohms.

Explanation:

<u>Given the following data;</u>

Capacitance = 0.1 uF = 0.0000001 Farad

Frequency = 50 Hz and 200 Hz

To find the capacitive reactance;

Mathematically, the capacitive reactance of an electronic circuit is given by the formula;

$X_{c} = \frac {1}{2 \pi fc}$

Where;

Xc is capacitive reactance.
f is the frequency.
c is the capacitance.

Substituting into the formula, we have;

I. At frequency, f = 50 Hz

$X_{c} = \frac {1}{2 * 3.142 * 50 * 0.0000001}$

$X_{c} = \frac {1}{314.2 * 0.0000001}$

$X_{c} = \frac {1}{0.00003142}$

$X_{c} = 31826.86$

II. At frequency, f = 200 Hz

$X_{c} = \frac {1}{2 * 3.142 * 200 * 0.0000001}$

$X_{c} = \frac {1}{1256.8 * 0.0000001}$

$X_{c} = \frac {1}{0.00012568}$

$X_{c} = 7956.72$

5 0

3 years ago

A round bar of chromium steel, (ρ= 7833 kg/m, k =48.9 W/m-K, c =0.115 KJ/kg-K, α=3.91 ×10^-6 m^2/s) emerges from a heat treatmen

Lerok [7]

Answer:

Q = 424523.22 kw

Explanation:

$\rho =7833 kg/m$

k = 48.9 W/m - K

c = 0.115 KJ/kg- K

$\alpha = 3.91*10^{-6} m^2/s$

$T_s = 285 degree celcius$

T_∞ = 35 degree celcius

velocity of air stream = 15 m/s

D = 40 cm

L = 200 cm

mass flow rate $\dot m = \rho AV = 7833 *\frac{\pi}{4} 0.4^2*15$

$\dot m = 14764.85 kg/s$

$A_s = \pi DL = \pi 0.4*2 = 2.513 m^2$

$Q = \dot m C \Delta T = h A_s \Delta T$

$\dot m C \Delta T = h A_s \Delta T$

solving for h

$h = \frac{14764.85*0.115*(285-35)}{2.513*(285-35)}$

h = 675.6 kw/m^2K

$Q = h A_s\Delta T$

Q = 675.6*2.513*(285-35)

Q = 424523.22 kw

7 0

3 years ago

Plant scientists would not do which of the following?

zavuch27 [327]

Explanation:

i think option 4 is correct answer because itsrelated to animal not plants.

6 0

4 years ago

Read 2 more answers