Answer:
F = 0.0022N
Explanation:
Given:
Surface area (A) = 4,000mm² = 0.004m²
Viscosity = µ = 0.55 N.s/m²
u = (5y-0.5y²) mm/s
Assume y = 4
Computation:
F/A = µ(du/dy)
F = µA(du/dy)
F = µA[(d/dy)(5y-0.5y²)]
F = (0.55)(0.004)[(5-1(4))]
F = 0.0022N
Technical Drawings give a better understanding of what is needed and required in the project.
Explanation:
I THINK THE ANSWER IS B BUT IM NOT SURE OK BYE
Answer:
Net discharge per hour will be 3.5325 
Explanation:
We have given internal diameter d = 25 mm
Time = 1 hour = 3600 sec
So radius 
We know that area is given by

We know that discharge is given by
, here A is area and V is velocity
So 
So net discharge in 1 hour = 
Answer:
Answer D
Explanation:
They need to be checked monthly