All categories

3 years ago

Mason deposited $763.21 in a savings account that earns 1.7% simple interest. What is Mason's account balance after nine years?

1 answer:

jeka943 years ago

8 0

The formula is
A=p (1+rt)
A future value?
P present value 763.21
R interest rate 0.017
T time 9 years

A=763.21×(1+0.017×9)
A=879.98

Hope it helps!

You might be interested in

The area of a circle is 2464cm2.calculate it's diameter to 2 significant figures<br>

tigry1 [53]

Answer:

Step-by-step explanation:

Answer:

The diameter of the circle is 56 cm.

Step-by-step explanation:

Given : The area of the circle is 2464 cm square.

To find : The diameter of the circle?

Solution :

The area of the circle is defined as

Where, A=2464 cm² is the area,

r is the radius

Substituting the values,

Radius of the circle is 28 cm.

The diameter of the circle is

Therefore, The diameter of the circle is 56 cm.

3 0

3 years ago

A regular hexagon has an area of 750.8 cm. The side length is 17 cm. Find the apothem.

kompoz [17]

Since, a regular hexagon has an area of 750.8 square cm and The side length is 17 cm.

We have to find the apothem of the regular hexagon.

The formula for determining the apothem of regular hexagon is $s \div {{2 \tan (\frac{180}{n})}$ , where 's' is any side length of regular hexagon and 'n' is the number of sides of regular hexagon.

So, apothem = $17 \div {2 tan(\frac{180}{6})$

= $17 \div {2 tan(30)$

= $17 \div {1.15}$

= 14.78 units

Therefore, the measure of apothem of the regular hexagon is 14.7 units.

Option B is the correct answer.

5 0

3 years ago

Math-- Farmer Bill has 500 meters of fencing and wants to enclose a rectangular plot that borders on a river. If farmer Bill doe

bixtya [17]

Answer:

Required dimensions of the rectangle are L = 200 m, W = 100 m

The largest area that can be enclosed is 20,000 sq m.

Step-by-step explanation:

The available length of the fencing = 500 m

Now, Perimeter of a rectangle = SUM OF ALL SIDES = 2(L+B)

But, here once side of the rectangle is NOT FENCED.

So, the required perimeter

= Perimeter of Complete field - Boundary of 1 open side

= 2(L+ W) - L = 2W + L

Now, fencing is given as 500 m

⇒ 2W + L = 500

Now, to maximize the length and width:

put L = 200, W = 100

we get 2(W) +L = 2(200) + 100 = 500 m

Hence, required dimensions of the rectangle are L = 200 m, W = 100 m

The maximized area = Length x Width

= 200 m x 100 m = 20, 000 sq m

Hence, the largest area that can be enclosed is 20,000 sq m.

6 0

3 years ago

Express a(2) (2a(-1/2)+a) in its simplest form

Soloha48 [4]

First lets simplify the first term and yield (2a)

The second term:
1. 2a * (-1/2) = -a
2. -a + a = 0

Now we have simplified both terms to: (2a) (0)

Anything multiplied by 0 is 0, so the answer is also 0.

4 0

4 years ago

Read 2 more answers

Given that R = 8 x + 4 y Find y when x = 8 and R = 30 Give your answer as an improper fraction in its simplest form.

Maksim231197 [3]

Answer:

y = -17/2

Step-by-step explanation:

Substitute with the givens.

30= 8(8) + 4y.

Multiply parentheses.

30 = 64 + 4y

Subtract.

30-64= -34

-34 = 4y.

Divide each side by 4.

y = - 8.5, or -17/2

hope that is right!

8 0

3 years ago