Question

Q|C A string with linear density 0.500 g/m is held under tension 20.0 N. As a transverse sinusoidal wave propagates on the string, elements of the string move with maximum speed v_{y, max } . (c) Find the energy contained in a section of string 3.00 \mathrm{~m} long as a function of v_{y, max } .

Answer 1

A string with linear density 0.500 g/m.

Tension 20.0 N.

The maximum speed  $v_{y, max}$

The energy contained in a section of string 3.00 m long as a function of $v_{y, max}$.

We are given following data for string with linear density held under tension :

μ = 0.5 $\frac{g}{m}$

  = 0.5 x 10⁻³ $\frac{kg}{m}$

T = 20 N

If string is L = 3m long, total energy as a function of $v_{y, max}$ is given by:

E = 1/2 x μ x L x ω² x A²

  = 1/2 x μ x L x $v^{2} _{y, max}$

  = 7.5 x 10⁻⁴ $v^{2} _{y, max}$

So, The total energy as a function of  $v^{2} _{y, max}$ = 7.5 x 10⁻⁴ $v^{2} _{y, max}$

Learn more about linear density problem here:

brainly.com/question/17190616

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