Question

Greg throws a 2.8-kg pumpkin horizontally off the top of the school roof in order to hit Mr. H's car. The car has parked a distance of 13.4 m away from the base of the building below the point where Greg is standing. The building's roof is 10.4 m high. Assuming no air resistance, with what horizontal speed does Greg toss the pumpkin in order to hit Mr. H's car

Answer 1

Answer:

The horizontal velocity is $v = 9.2 m/s$

Explanation:

From the question we are told that

     The mass of the pumpkin is  $m = 2.8 \ kg$

      The distance of the the car from the building's base is  $d = 13.4 \ m$

       The height of the roof is $h = 10.4 \ m$

       

The height is mathematically represented as

         $h = \frac{1}{2} gt^2$

Where g is the acceleration due to gravity which has a value of $g =9.8 \ m/s^2$

substituting values

          $10.4= 0.5 * 9.8 * t$

making the time taken the subject of the formula

         $t = \frac{10.4}{0.5 * 9.8 }$

          $t = 1.457 \ s$

The speed at which the pumpkin move horizontally can be represented mathematically  as

                         $v = \frac{d}{t}$

substituting values

                     $v =\frac{13.4}{1.457}$

                     $v = 9.2 m/s$