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dmitriy555 [2]
2 years ago
14

How can having a mentor help individuals achieve their goals? A. Mentors can increase accountability. B. Mentors can increase mo

tivation. C. Mentors can identify areas that need additional work. D. all of the above Please select the best answer from the choices provided. A B C D
Physics
2 answers:
alexgriva [62]2 years ago
8 0

The answer is D. all of the above

lana [24]2 years ago
6 0

Your best bet is to go with D.

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i thinks answers is gap relutance increases linearly with magnetic density

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3 years ago
Can You Please Give Me Some Examples of Density-Independent and Density-Dependent Limiting Factors?
ivolga24 [154]
Density-Dependent: 
1<span><span><span><span>. </span>competition.</span><span>   
<span>2. </span>overcrowding.</span><span>   
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(These are a few from a test I took, hopefully they help you a bit >.<)</span></span>
7 0
3 years ago
Jake is in chemistry class. He makes a list of the chemicals his instructor described and the properties of each.
koban [17]
Silver: bonds with other atoms because of the weak forces of the valence electrons 
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6 0
3 years ago
Read 2 more answers
Particle q₁ has a charge of 2.7 μC and a velocity of 773 m/s. If it experiences a magnetic force of 5.75 × 10⁻³ N, what is the s
Ne4ueva [31]
The intensity of the magnetic force F experienced by a charge q moving with speed v in a magnetic field of intensity B is equal to
F=qvB \sin \theta
where \theta is the angle between the directions of v and B.

1) Re-arranging the previous formula, we can calculate the value of the magnetic field intensity. The charge is q=2.7 \mu C=2.7 \cdot 10^{-6}C. In this case, v and B are perpendicular, so \theta=90^{\circ}, therefore we have:
B= \frac{F}{qv \sin \theta} = \frac{5.75 \cdot 10^{-3}N}{(2.7 \cdot 10^{-6}C)(773m/s)\sin 90^{\circ}}=2.8 T

2) In this second case, the angle between v and B is \theta=55^{\circ}. The charge is now q=42.0 \mu C=42.0 \cdot 10^{-6}C, and the magnetic field is the one we found in the previous part, B=2.8 T, so we can find the intensity of the force experienced by this second charge:
F=qvB \sin \theta=(42\cdot 10^{-6}C)(1.21 \cdot 10^3 m/s)(2.8 T)(\sin 55^{\circ})=0.12 N
5 0
3 years ago
Read 2 more answers
How much force is needed to accelerate a 68 kilogram-skier at a rate of 1.2 m/sec^2?
DiKsa [7]
<span>Answer: Force = 81.6 N

Explanation:
According to Newton's Second law:
F = ma --- (1)

Where F = Force = ?
m = Mass = 68 kg
a = Acceleration = 1.2 m/s^2

Plug in the values in (1):
(1) => F = 68 * 1.2
F = 81.6 N (The force needed to accelerate the skier at a rate of 1.2 m/s^2)</span>
4 0
3 years ago
Read 2 more answers
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