What should be done to lift the same load by applying less effort on an inclined plane
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Answer:
Graphing the momentum against the change in moment yields a linear relationship.
Explanation:
This is an impulse experiment,
I = ∫ F .dt
where the force and time of the collision are measured, therefore if we assume an average force the integral reduces to
I = F t
Furthermore, the momentum is equal to the change in moment of the ball, this change in moment can be found using the energy relations measuring the height of the ball and calculating its speed, in the two intervals for the descent and for the exit, possibly the heights are different so the moment change is different from zero.
Starting point. Higher
Em₀ = U = mgh
Lower end point, just before hitting the scale
= K = ½ m v²
in the path in the air there is no friction
Em₀ = Em_{f}
m g h = ½ m v²
v =
this height is different for the descent and ascent of the ball, so we have two moments
Δp = - p₀
Δp = m (v_{f} -v₀)
therefore we have the relationship
I = Δp
Graphing the momentum against the change in moment yields a linear relationship.
The acceleration will be constantly equal to 1 m/s².Option c is correct.
<h3>What is force?</h3>Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.
Force is defined as the product of mass and acceleration. Its unit is Newton.
Given data;
Force,F = 350 N
Friction force,f=350 N
F=f
Because the frictional and applied forces on the two boxes are of equal strength, both move at the same pace. As a result, the acceleration will be constantly equal to 1 m/s².
Hence option c is correct.
To learn more about the force refer to the link;
brainly.com/question/26115859#SPJ1
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The time taken by the ballast bag to reach the ground is 2.18 s
The ballast bag at rest with respect to the balloon has the upward velocity (u) of 4.6 m/s , which is the velocity of the balloon. When it is dropped from the balloon, its motion is similar to an object thrown upwards with an initial velocity <em>u </em>and it falls under the acceleration due to gravity<em> g.</em>
Taking the upward direction as positive and the downward direction as negative, the following equation of motion may be used.
The bag makes a net displacement <em>s</em> of 13.4 m downwards, hence
Its initial velocity is
The acceleration due to gravity acts downwards and hence it is negative.
Use the values in the equation of motion and write an equation for t.
Solving the equation for t and taking only the positive value for t,
t=2.18 s